Problem 43
Question
In Exercises 35 - 44, write an expression for the \( n \)th term of the geometric sequence. Then find the indicated term. \( a_1 = 500, r = 1.02, n = 40 \)
Step-by-Step Solution
Verified Answer
Therefore, the 40th term of the geometric sequence is \( 500 \cdot (1.02)^{39} \).
1Step 1: Write out the general formula
The \( n \)th term, \( a_n \), of a geometric sequence can be found with the formula \( a_n = a_1 \cdot r^{n-1} \), where \( a_1 \) is the first term, \( r \) is the common ratio, and \( n \) is the term number.
2Step 2: Substitute the given values
By substituting the given values into the formula, you have \( a_n = 500 \cdot (1.02)^{40-1} \).
3Step 3: Simplify the expression
Simplify the expression to get the value of the 40th term. So, \( a_{40} = 500 \cdot (1.02)^{39} \).
Key Concepts
Geometric ProgressionCommon RatioSequence Term Calculation
Geometric Progression
A geometric progression is a sequence of numbers where each term after the first is found by multiplying the previous term by a constant called the common ratio. For instance, in the sequence 2, 4, 8, 16, each number is the result of multiplying the previous number by 2. This pattern of multiplication makes a geometric progression fundamentally different from an arithmetic progression, where you add a constant to get the next term. The ability to identify a geometric progression is important because it allows us to predict future terms and to calculate properties of the series, such as its sum.
When we speak of the 'n-th term' of a geometric sequence, we are referring to a specific element in the sequence that occupies the position 'n'. For example, the 3rd term in the sequence above is 8, and the 4th term is 16. A clear understanding of the geometric progression is crucial for working with growth or decay problems in fields as diverse as finance, physics, and biology, where this type of progression naturally appears.
When we speak of the 'n-th term' of a geometric sequence, we are referring to a specific element in the sequence that occupies the position 'n'. For example, the 3rd term in the sequence above is 8, and the 4th term is 16. A clear understanding of the geometric progression is crucial for working with growth or decay problems in fields as diverse as finance, physics, and biology, where this type of progression naturally appears.
Common Ratio
The common ratio of a geometric sequence is the factor by which consecutive terms multiply. If each term of the sequence is found by multiplying the previous term by the same number, that number is referred to as the common ratio, denoted by 'r'. For the sequence 3, 9, 27, 81, the common ratio is 3 because each term is three times the term before it.
Understanding the common ratio is vital for solving problems related to geometric sequences, as it is a key component in the formula used to find the terms of the sequence. To identify the common ratio, you can divide any term in the sequence by the preceding term. For example, if you have the sequence 5, 15, 45, dividing 15 by 5 or 45 by 15 will both yield the common ratio 3.
Understanding the common ratio is vital for solving problems related to geometric sequences, as it is a key component in the formula used to find the terms of the sequence. To identify the common ratio, you can divide any term in the sequence by the preceding term. For example, if you have the sequence 5, 15, 45, dividing 15 by 5 or 45 by 15 will both yield the common ratio 3.
Sequence Term Calculation
To calculate the nth term of a geometric sequence, we use the formula: \( a_n = a_1 \times r^{(n-1)} \), where \( a_n \) is the nth term we wish to find, \( a_1 \) is the first term of the sequence, 'r' is the common ratio, and 'n' is the term's position in the sequence. By substituting the known values into this formula, we can determine any term's value.
For instance, with a first term \( a_1 \) of 500 and a common ratio 'r' of 1.02, to find the 40th term, we denote 'n' as 40 and use the formula to compute \( a_{40} = 500 \times (1.02)^{39} \). Through this calculation, the monumental power of geometric sequences becomes apparent, as we can see how a small change in the common ratio compounds dramatically over a large number of terms, which is especially relevant in the contexts of compound interest and exponential growth.
For instance, with a first term \( a_1 \) of 500 and a common ratio 'r' of 1.02, to find the 40th term, we denote 'n' as 40 and use the formula to compute \( a_{40} = 500 \times (1.02)^{39} \). Through this calculation, the monumental power of geometric sequences becomes apparent, as we can see how a small change in the common ratio compounds dramatically over a large number of terms, which is especially relevant in the contexts of compound interest and exponential growth.
Other exercises in this chapter
Problem 43
In Exercises 41 - 44, expand the binomial by using Pascals Triangle to determine the coefficients \( \left(x + 2y\right)^5 \)
View solution Problem 43
In Exercises 43 - 48, find a formula for the sum of the first \( n \) terms of the sequence. \( 1, 5, 9, 13, \cdots \)
View solution Problem 43
In Exercises 41 - 46, write the first five terms of the arithmetic sequence defined recursively. \( a_1 = 200, a_{n + 1} = a_n - 10 \)
View solution Problem 44
In Exercises 43 - 46, find the number of distinguishable permutations of the group of letters. \( B, B, B, T, T, T, T, T, \)
View solution