Problem 43
Question
A rectangle with length \(2 x+5\) inches has an area of \(2 x^{4}+15 x^{3}+7 x^{2}-135 x-225\) square inches. Write a polynomial that represents its width.
Step-by-Step Solution
Verified Answer
The polynomial that represents the width of the rectangle is \(x^{3}+5x^{2}-6x-45\)
1Step 1: Formulate the Equation for Width
The formula for the area of a rectangle equals length times width (Area = Length*Width). Therefore, the width is equal to the area divided by the length. Write the equation as \(Width = \frac{Area}{Length}\).
2Step 2: Substitute the Given Values
Substitute the given values for area and length into the equation obtained in Step 1: \(Width = \frac{2 x^{4}+15 x^{3}+7 x^{2}-135 x-225}{2x+5}\) .
3Step 3: Dividing Polynomial
Divide the polynomial in order to reduce it to the simplest form. The result comes as \(x^{3}+5x^{2}-6x-45\).
Key Concepts
Understanding Rectangle AreaExploring Polynomial ExpressionsWidth Calculation from Area and Length Using Polynomial Division
Understanding Rectangle Area
Finding the area of a rectangle is a fundamental concept in geometry that helps us determine the size of a space. When you think about the area of a rectangle, it's about figuring out how much flat space it covers. Here, we focus on multiplying the length and width to get the area. The formula to remember is:
- Area = Length × Width
Exploring Polynomial Expressions
A polynomial is an expression that involves variables raised to various powers, combined using addition, subtraction, and sometimes multiplication. In the given exercise, each component of the rectangle's area is part of a polynomial expression. This might look complex initially, but it’s a structured and logical way to represent numbers and operations.
Consider the polynomial in our exercise:
Consider the polynomial in our exercise:
- The area expression is: \[2x^{4} + 15x^{3} + 7x^{2} - 135x - 225\]
- The length expression is: \[2x + 5\]
Width Calculation from Area and Length Using Polynomial Division
Calculating the width of a rectangle when given its area and length requires a logical process, specifically when dealing with polynomials. We performed polynomial division to find the width.
Here's how it works:
Here's how it works:
- Start with the equation for width: \[\text{Width} = \frac{\text{Area}}{\text{Length}}\]
- Substitute the given polynomial expressions for the area and length into this equation.
- This means you will divide: \[\frac{2x^{4} + 15x^{3} + 7x^{2} - 135x - 225}{2x + 5}\]
- The calculated width becomes: \[x^{3} + 5x^{2} - 6x - 45\]
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