Problem 41
Question
Use synthetic division and the Remainder Theorem to evaluate \(P(c) .\) \(P(x)=x^{3}+2 x^{2}-7, \quad c=-2\)
Step-by-Step Solution
Verified Answer
\(P(-2) = -7\)
1Step 1: Set up synthetic division
Write down the coefficients of the polynomial \(P(x) = x^3 + 2x^2 + 0x - 7\), which are \(1, 2, 0, -7\). We use \(c = -2\) for the division.
2Step 2: Perform synthetic division
Bring down the leading coefficient, which is \(1\). Multiply \(1\) by \(-2\) and add to the next coefficient (\(2\)): \(1 \times -2 + 2 = 0\). Repeat for the rest: \(0 \times -2 + 0 = 0\); \(0 \times -2 - 7 = -7\).
3Step 3: Interpret the remainder
The result of the synthetic division gives us a remainder of \(-7\). According to the Remainder Theorem, this is \(P(-2)\).
Key Concepts
Polynomial EvaluationRemainder TheoremAlgebraic Expressions
Polynomial Evaluation
Polynomial evaluation is like checking how a specific value affects the equation. Here, we're determining the result of a polynomial when a certain number replaces the variable. For this exercise, we have a polynomial function \(P(x) = x^3 + 2x^2 - 7\) to evaluate at \(c = -2\).
Using synthetic division makes this process quicker compared to simply substituting and calculating, especially for complex polynomials. By organizing the coefficients \(1, 2, 0, -7\) and employing \(c = -2\), we streamline the calculation through a step-by-step approach.
Using synthetic division makes this process quicker compared to simply substituting and calculating, especially for complex polynomials. By organizing the coefficients \(1, 2, 0, -7\) and employing \(c = -2\), we streamline the calculation through a step-by-step approach.
- Start by jotting down the polynomial's coefficients.
- Use the divisor, here \(-2\), and begin the process of synthetic division.
Remainder Theorem
The Remainder Theorem is a handy tool that connects polynomial division to function evaluation. It states that the remainder obtained from dividing a polynomial by a binomial \((x - c)\) is precisely the value of the polynomial at that same \(c\).
This theorem simplifies the evaluation process vastly. Instead of substituting and simplifying the expression, you simply divide and find the remainder, which directly gives you \(P(c)\).
This theorem simplifies the evaluation process vastly. Instead of substituting and simplifying the expression, you simply divide and find the remainder, which directly gives you \(P(c)\).
- Arrange your polynomial for division by noting its coefficients.
- Apply synthetic division to save time and effort.
Algebraic Expressions
Understanding algebraic expressions is foundational in maneuvering through polynomial problems. An algebraic expression is a combination of variables, coefficients, and constants, involving operations like addition or subtraction.
In the exercise given, \(P(x) = x^3 + 2x^2 - 7\) is an instance of an algebraic expression. Each part is called a term, with coefficients attached to variables and constants standing alone.
In the exercise given, \(P(x) = x^3 + 2x^2 - 7\) is an instance of an algebraic expression. Each part is called a term, with coefficients attached to variables and constants standing alone.
- The expression is built from different terms: \(x^3\), \(2x^2\), and \(-7\).
- It's crucial to remember when finding the value of \(P(c)\), each term contributes collectively towards the end result after evaluation.
Other exercises in this chapter
Problem 41
Find all the real zeros of the polynomial. Use the quadratic formula if necessary, as in Example 3(a). $$ P(x)=x^{3}+4 x^{2}+3 x-2 $$
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\(41-58=\) Find all zeros of the polynomial. $$ P(x)=x^{3}-7 x^{2}+17 x-15 $$
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Find the intercepts and asymptotes, and then sketch a graph of the rational function. Use a graphing device to confirm your answer. \(s(x)=\frac{2 x-4}{x^{2}+x-
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