Problem 41
Question
For the following exercises, two dice are rolled, and the results are summed. Find the probability of rolling a sum of 5 or 6 .
Step-by-Step Solution
Verified Answer
The probability of rolling a sum of 5 or 6 is 1/4.
1Step 1: Understanding Dice Roll Outcomes
When two dice are rolled, each die has 6 possible outcomes (1 through 6). Therefore, there are a total of 6 x 6 = 36 different possible outcomes for the roll of two dice. Each outcome is equally likely.
2Step 2: Identifying Favorable Outcomes for a Sum of 5
To have a sum of 5, the following pairs of dice must be rolled: (1,4), (2,3), (3,2), or (4,1). There are 4 combinations that result in a sum of 5.
3Step 3: Identifying Favorable Outcomes for a Sum of 6
For a sum of 6, the pairs of dice needed are: (1,5), (2,4), (3,3), (4,2), or (5,1). This gives us 5 different combinations that sum to 6.
4Step 4: Calculating Total Favorable Outcomes
Add the number of favorable outcomes for both sums. There are 4 outcomes for a sum of 5 and 5 outcomes for a sum of 6, totalling to 4 + 5 = 9 favorable outcomes.
5Step 5: Calculating Probability of Rolling a 5 or 6
The probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. Therefore, the probability of rolling a sum of 5 or 6 is 9/36, which simplifies to 1/4.
Key Concepts
Dice ProbabilitiesSum of Two DiceFavorable OutcomesCalculating Probability
Dice Probabilities
When it comes to understanding the probabilities associated with dice, it's essential to start with the basics. Each die in a pair has six faces, numbered 1 through 6. When rolling two dice together, you increase the range of possible outcomes. Every roll of two dice results in a combination of the two numbers, leading to a total of 36 possible outcomes. Imagine each die independently, and you'll realize that each outcome is equally likely. This is because the result of one die does not influence the other die. Given that each combination is equally possible, we say that each outcome has a probability of 1/36.
Sum of Two Dice
One intriguing aspect of rolling two dice is calculating the likelihood of various sums. The smallest possible sum is 2 (1 + 1), and the largest is 12 (6 + 6). Between these extremes, you can achieve sums like 5 or 6, which are the sums we are interested in for this problem. Each sum is the result of different combinations of the values on both dice. For instance:
- To get a sum of 5, you might roll (1,4), (2,3), (3,2), or (4,1).
- For a sum of 6, you could toss a (1,5), (2,4), (3,3), (4,2), or (5,1).
Favorable Outcomes
In probability, 'favorable outcomes' are those outcomes which satisfy the conditions of the event we're considering. For the problem we have, a 'favorable outcome' is any roll of two dice that results in a sum of either 5 or 6.
We have already identified specific combinations that produce these sums.
We have already identified specific combinations that produce these sums.
- There are 4 favorable outcomes resulting in a 5.
- 5 different combinations yield a sum of 6.
Calculating Probability
Probability in mathematics measures how likely an event is to occur.
The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. In the dice example, once we've determined there are 9 favorable outcomes for rolling a sum of 5 or 6, we see:
The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. In the dice example, once we've determined there are 9 favorable outcomes for rolling a sum of 5 or 6, we see:
- Total possible outcomes = 36 (from rolling two dice)
- Favorable outcomes = 9 (combinations yielding 5 or 6)
Other exercises in this chapter
Problem 40
For the following exercises, evaluate the factorial. $$ \left(\frac{12}{6}\right) ! $$
View solution Problem 40
Evaluate the factorial. $$\left(\frac{12}{6}\right) !$$
View solution Problem 41
Use the formula for the sum of the first \(n\) terms of a geometric series to find the partial sum. $$ \sum_{n=1}^{10}-2 \cdot\left(\frac{1}{2}\right)^{n-1} $$
View solution Problem 41
A cell phone company offers 6 different voice packages and 8 different data packages. Of those, 3 packages include both voice and data. How many ways are there
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