Problem 41
Question
Exer. 1-50: Verify the identity. $$ \left(1-\tan ^{2} \phi\right)^{2}=\sec ^{4} \phi-4 \tan ^{2} \phi $$
Step-by-Step Solution
Verified Answer
The identity \((1-\tan^2 \phi)^2 = \sec^4 \phi - 4\tan^2 \phi\) is verified.
1Step 1: Recognize trigonometric identities
Recall that the tangent and secant functions are related through the identity \( \sec^2 \phi = 1 + \tan^2 \phi \). We will use this identity to simplify the given equation.
2Step 2: Expand the left side
Expand \( (1 - \tan^2 \phi)^2 \) using the formula for the square of a binomial: \( (a - b)^2 = a^2 - 2ab + b^2 \). This results in: \[ (1 - \tan^2 \phi)^2 = 1 - 2\tan^2 \phi + \tan^4 \phi. \]
3Step 3: Simplify the right side
Substitute \( \sec^2 \phi \) in the right side of the equation using \( \sec^2 \phi = 1 + \tan^2 \phi \) to express \( \sec^4 \phi \) as:\[ \sec^4 \phi = (1 + \tan^2 \phi)^2. \]
4Step 4: Expand \( \sec^4 \phi \)
Now expand \( (1 + \tan^2 \phi)^2 \): \[ (1 + \tan^2 \phi)^2 = 1 + 2\tan^2 \phi + \tan^4 \phi. \]
5Step 5: Substitute and compare
Substitute the expansion from Step 4 into the simplified right side equation:\[ \sec^4 \phi - 4\tan^2 \phi = 1 + 2\tan^2 \phi + \tan^4 \phi - 4\tan^2 \phi. \]Simplify this to:\[ 1 - 2\tan^2 \phi + \tan^4 \phi. \]
6Step 6: Verify the identity
Compare the simplified expressions from the left and right sides:* Left side: \( 1 - 2\tan^2 \phi + \tan^4 \phi \)* Right side: \( 1 - 2\tan^2 \phi + \tan^4 \phi \)Since both expressions are identical, the identity is verified.
Key Concepts
Tangent FunctionSecant FunctionAlgebraic ManipulationTrigonometric Equations
Tangent Function
The tangent function (\( \tan \phi \)) is one of the basic trigonometric functions. It is often used in various mathematical and engineering fields. Understanding the tangent function is essential as it helps in solving different problems involving angles and ratios.
- Definition: The tangent of an angle in a right triangle is the ratio of the opposite side to the adjacent side.
- Expression: Mathematically, \( \tan \phi = \frac{\text{Opposite}}{\text{Adjacent}} \).
Secant Function
The secant function is another fundamental trigonometric function. It has a critical role especially when it comes to verifying identities involving tangent.
- Definition: The secant of an angle is the reciprocal of the cosine function, which is \( \sec \phi = \frac{1}{\cos \phi} \).
- Expression: It is closely related to the tangent function through the identity \( \sec^2 \phi = 1 + \tan^2 \phi \).
Algebraic Manipulation
Algebraic manipulation is an essential skill in mathematics, especially when dealing with trigonometric identities. These manipulations allow us to transform and simplify expressions, as we did in solving the given exercise.
- Expansion: Using identities like \((a-b)^2 = a^2 - 2ab + b^2\) helps in expanding expressions.
- Substitution: Replacing parts of an equation using known identities such as \( \sec^2 \phi = 1 + \tan^2 \phi \) is a powerful tool.
Trigonometric Equations
Trigonometric equations involve values of trigonometric functions of unknown angles. Solving them requires an understanding of the basic trigonometric functions and identities.
- Solving Process: Often involves substitution and algebraic manipulation to transform the equations into a more solvable form.
- Verification: After solving, it's crucial to verify that solutions satisfy the original equation.
Other exercises in this chapter
Problem 41
Exer. 33-42: Sketch the graph of the equation. $$ y=\sin (\arccos x) $$
View solution Problem 41
Exer. 39-62: Find the solutions of the equation that are in the interval \([0,2 \pi\) ). $$ 2-8 \cos ^{2} t=0 $$
View solution Problem 41
Exer. 37-46: Verify the identity. $$ \cos (u+v)+\cos (u-v)=2 \cos u \cos v $$
View solution Problem 41
Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$ \sin \frac{1}{2} u+\cos u=1 $$
View solution