Problem 40
Question
Without expanding, what is the leading term of $$ (2 s+5)(3 s+1)(s-10) ? $$
Step-by-Step Solution
Verified Answer
Answer: The leading term of the polynomial is \(6s^3\).
1Step 1: Identify the leading terms of each binomial
In each binomial, the leading term is the term with the highest power of the variable \(s\):
- For the first binomial \((2s+5)\), the leading term is \(2s\)
- For the second binomial \((3s+1)\), the leading term is \(3s\)
- For the third binomial \((s-10)\), the leading term is \(s\)
2Step 2: Multiply the leading terms
Now, to get the leading term of the entire polynomial, multiply the leading terms we identified in step 1:
$$(2s) \times (3s) \times (s)$$
3Step 3: Simplify the leading term
Finally, simplify the expression we got in step 2:
$$6s^3$$
Thus, the leading term of the given polynomial is \(\boxed{6s^3}\).
Key Concepts
Understanding the Binomial Leading TermMultiplying BinomialsSimplifying Expressions
Understanding the Binomial Leading Term
When dealing with binomials, it's important to identify the leading term. The leading term is the term with the highest power of the variable.
In binomial expressions like \((2s + 5)\), \((3s + 1)\), and \((s - 10)\), you look for the term involving the variable raised to the highest power, which is usually the first term.
For example:
The leading terms form the building blocks to determine the overall behavior of the polynomial when multiplied with each other.
In binomial expressions like \((2s + 5)\), \((3s + 1)\), and \((s - 10)\), you look for the term involving the variable raised to the highest power, which is usually the first term.
For example:
- In \((2s + 5)\), the leading term is \(2s\), because the "\(s\)" is of the first power, and it is the main focus compared to the constant \(5\).
- In \((3s + 1)\), the leading term is \(3s\).
- In \((s - 10)\), the leading term is \(s\).
The leading terms form the building blocks to determine the overall behavior of the polynomial when multiplied with each other.
Multiplying Binomials
To understand how binomials interact, we often multiply them. This process involves dealing with each part of the expression, especially their leading terms.
Suppose you want to find the leading term of the product of several binomials like in our example:
\[ (2s) \times (3s) \times (s) = 6s^3 \]
This focuses on multiplying the coefficients \(2\), \(3\), and the implicit \(1\) in \(s\) together, and then combining the powers of \(s\).
The result \(6s^3\) represents the highest degree term of the new polynomial created by multiplying the three binomials together.
Suppose you want to find the leading term of the product of several binomials like in our example:
- The leading term of \((2s + 5)(3s + 1)(s - 10)\) can be found by multiplying the leading terms: \((2s)\), \((3s)\), and \((s)\).
\[ (2s) \times (3s) \times (s) = 6s^3 \]
This focuses on multiplying the coefficients \(2\), \(3\), and the implicit \(1\) in \(s\) together, and then combining the powers of \(s\).
The result \(6s^3\) represents the highest degree term of the new polynomial created by multiplying the three binomials together.
Simplifying Expressions
Simplifying polynomial expressions involves reducing them to their most basic form. This often means combining like terms and eliminating redundancies.
In the context of leading terms, the goal is to ensure you're dealing with the most straightforward representation of the term. After multiplying the leading terms,
The simplified form \(6s^3\) is crucial because it tells us how this polynomial behaves for large values of \(s\). It reflects both the degree and the leading coefficient, providing insight into the polynomial's growth and direction.
In the context of leading terms, the goal is to ensure you're dealing with the most straightforward representation of the term. After multiplying the leading terms,
- We find \(6s^3\) as the simplified leading term.
- Combining all the coefficients: \((2 \times 3 = 6)\).
- Adding the powers of \(s\): \(1 + 1 + 1 = 3\), giving us \(s^3\).
The simplified form \(6s^3\) is crucial because it tells us how this polynomial behaves for large values of \(s\). It reflects both the degree and the leading coefficient, providing insight into the polynomial's growth and direction.
Other exercises in this chapter
Problem 39
For what value(s) of the constant \(a\) does \(\left(x^{2}-a^{2}\right)(x+1)=0\) have exactly two solutions?
View solution Problem 40
For what values of \(a\) does the equation have a solution in \(x\) ? $$ x^{2}-a=0 $$
View solution Problem 41
What is the degree and leading coefficient of the polynomial \(r(x)=4 ?\)
View solution Problem 41
For what values of \(a\) does the equation have a solution in \(x\) ? $$ 2 x^{2}+a=0 $$
View solution