Problem 40
Question
Sketch the surfaces in Exercises \(13-76\) $$ \left(y^{2} / 4\right)-\left(x^{2} / 4\right)-z^{2}=1 $$
Step-by-Step Solution
Verified Answer
The surface is a hyperboloid of two sheets, symmetric about the y-axis.
1Step 1: Identify the Type of Surface
The given equation \( \left(y^{2} / 4\right)-\left(x^{2} / 4\right)-z^{2}=1 \) resembles the general form of a hyperboloid of two sheets.
2Step 2: Rewrite the Equation
To make it clearer, rewrite the equation as \( \frac{y^2}{4} - \frac{x^2}{4} - z^2 = 1 \). Notice that the \( y^2 \) term and \( x^2 \) term both have the same denominator, indicating symmetry in the \( x-y \) plane.
3Step 3: Analyze Cross Sections
Set \( z = 0 \), which results in the equation \( \frac{y^2}{4} - \frac{x^2}{4} = 1 \), this is a hyperbola in the \( x-y \) plane. If you set \( x = 0 \), the equation becomes \( \frac{y^2}{4} - z^2 = 1 \), another hyperbola in the \( y-z \) plane.
4Step 4: Identify Symmetry
The surface is symmetric about the \( y \)-axis since the equation can be rewritten with \( y \) as having a positive coefficient while \( x \) and \( z \) have negative coefficients. This suggests the surface extends along the \( y \)-axis.
5Step 5: Sketch the Surface
Using the information from the cross sections, sketch two opposing bowls (one below and one above the point \( y=0 \)). These open along the \( y \)-axis, forming a hyperboloid of two sheets. The intersection with the \( y \) axis is along the hyperboloid's \( y \) direction.
Key Concepts
Surfaces in Multivariable CalculusCross Sections of SurfacesSymmetry in Surfaces
Surfaces in Multivariable Calculus
In multivariable calculus, the concept of surfaces can be compared to exploring three-dimensional structures in space. One such surface, highlighted by the equation \( \frac{y^2}{4} - \frac{x^2}{4} - z^2 = 1 \), is the hyperboloid of two sheets. This surface is a fascinating example due to its unique structure of two separate, opposing bowls that open in opposite directions. When we analyze its mathematical representation, we can glean insights about the nature of three-dimensional space.
- The signs and coefficients of each squared term in the equation give clues about the shape's structure and orientation.
- The term with a positive coefficient (in this case \( y^2 \)) indicates the axis along which the surface opens.
Cross Sections of Surfaces
When exploring surfaces, a useful tool is analyzing cross sections, which are basically slices of the surface taken parallel to various planes. For the hyperboloid of two sheets represented by the given equation, examining these cross sections enriches our understanding of its shape.
- Setting \( z = 0 \) transforms the equation into \( \frac{y^2}{4} - \frac{x^2}{4} = 1 \), sketching a hyperbola in the \( x-y \) plane.
- Likewise, setting \( x = 0 \) changes it to \( \frac{y^2}{4} - z^2 = 1 \), which is a hyperbolic curve in the \( y-z \) plane.
Symmetry in Surfaces
Symmetry is a fundamental concept in geometry that greatly simplifies the understanding and representation of surfaces. In the equation \( \frac{y^2}{4} - \frac{x^2}{4} - z^2 = 1 \), symmetry plays a key role. The surface shows symmetry with respect to the \( y \)-axis due to the positive coefficient of \( y^2 \).
- Symmetry about the \( y \)-axis implies that the shape of the surface is mirrored on either side of this axis.
- Furthermore, the identical coefficients of \( x^2 \) and \( y^2 \) suggest rotational symmetry along the \( y \)-axis.
Other exercises in this chapter
Problem 39
In Exercises \(35-40,\) find the distance between points \(P_{1}\) and \(P_{2}\) $$ P_{1}(0,0,0), \quad P_{2}(2,-2,-2) $$
View solution Problem 39
If \(\overrightarrow{A B}=\mathbf{i}+4 \mathbf{j}-2 \mathbf{k}\) and \(B\) is the point \((5,1,3),\) find \(A\)
View solution Problem 40
Find the areas of the triangles whose vertices are given in Exercises \(39-42\) $$ A(-1,-1), \quad B(3,3), \quad C(2,1) $$
View solution Problem 40
In Exercises 39–44, find the distance from the point to the plane. $$ (0,0,0), \quad 3 x+2 y+6 z=6 $$
View solution