Problem 39
Question
In Exercises \(35-40,\) find the distance between points \(P_{1}\) and \(P_{2}\) $$ P_{1}(0,0,0), \quad P_{2}(2,-2,-2) $$
Step-by-Step Solution
Verified Answer
The distance between the points is \(2\sqrt{3}\).
1Step 1: Identify the Coordinates
The coordinates of point \( P_1 \) are \((0, 0, 0)\) and the coordinates of point \( P_2 \) are \((2, -2, -2)\).
2Step 2: Use the Distance Formula
The distance \( d \) between two points in 3-dimensional space, \((x_1, y_1, z_1)\) and \((x_2, y_2, z_2)\), is given by the formula: \( d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2} \).
3Step 3: Substitute the Coordinates
Plug the coordinates of \( P_1 \) and \( P_2 \) into the distance formula: \( d = \sqrt{(2-0)^2 + (-2-0)^2 + (-2-0)^2} \).
4Step 4: Simplify the Expression
Calculate the difference for each pair of coordinates and simplify: \( d = \sqrt{2^2 + (-2)^2 + (-2)^2} = \sqrt{4 + 4 + 4} \).
5Step 5: Calculate the Distance
Add the values under the square root and then compute the square root: \( d = \sqrt{12} = 2\sqrt{3} \).
Key Concepts
3-dimensional spacecoordinate geometryEuclidean distance
3-dimensional space
In mathematics, three-dimensional space refers to a geometric setting in which three values are required to determine the position of an element (i.e., a point). Just like how two-dimensional space uses an x-axis and y-axis, three-dimensional space adds a z-axis. This extra dimension allows us to represent any location within our world, which we often think of as having length, width, and height. In
Understanding this concept helps us apply geometric principles beyond just flat shapes to more practical, real-world volumes and forms.
- Physics, we use it to model the physical universe.
- Engineering, for creating 3D models.
- Computer graphics, in the design of realistic video game environments.
Understanding this concept helps us apply geometric principles beyond just flat shapes to more practical, real-world volumes and forms.
coordinate geometry
Coordinate geometry, also known as analytic geometry, merges algebra and geometry by using a coordinate system to define geometric shapes. This branch of geometry allows us to perform calculations on geometric objects by representing them with numerical coordinates. For example, in 2D, a point is defined by two coordinates,
extit{x} for horizontal position and
extit{y} for vertical. In 3D, we include a third coordinate:
extit{z} for depth.
- This approach simplifies the analysis of geometric shapes.
- Facilitates solving complex geometric problems using algebraic equations.
- Helps in visualizing geometrical objects and measuring distances easily.
Euclidean distance
Euclidean distance is a concept from mathematics that measures the straight-line distance between two points in Euclidean space. It's the most basic form of distance and is widely used in various fields like computer science, physics, and machine learning. The formula for Euclidean distance in 2D space is \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\). In 3D space, we extend this to include the z-coordinate: \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}\).
- It's derived from the Pythagorean theorem.
- Offers a straightforward method to compare distances in various dimensions.
- Essential in algorithms that require similarity measurements.
Other exercises in this chapter
Problem 39
Find the areas of the triangles whose vertices are given in Exercises \(39-42\) $$ A(0,0), \quad B(-2,3), \quad C(3,1) $$
View solution Problem 39
In Exercises 39–44, find the distance from the point to the plane. $$ (2,-3,4), \quad x+2 y+2 z=13 $$
View solution Problem 39
If \(\overrightarrow{A B}=\mathbf{i}+4 \mathbf{j}-2 \mathbf{k}\) and \(B\) is the point \((5,1,3),\) find \(A\)
View solution Problem 40
Sketch the surfaces in Exercises \(13-76\) $$ \left(y^{2} / 4\right)-\left(x^{2} / 4\right)-z^{2}=1 $$
View solution