Problem 40
Question
In Exercises 19 - 40, use the Binomial Theorem to expand and simplify the expression. \( \left(4x - 1\right)^3 - 2\left(4x - 1\right)^4 \)
Step-by-Step Solution
Verified Answer
The expanded and simplified form of the given expression using the Binomial Theorem is \( -512x^4 + 576x^3 - 240x^2 + 44x - 3 \).
1Step 1: Expanding the first term
Expand \( \left(4x - 1\right)^3 \) using the Binomial theorem. By using the binomial theorem, \( (a + b)^n = \sum{n \choose k} a^{n-k}b^k \), where \(n \choose k\) is binomial coefficient. \n So, \( (4x - 1)^3 = {3 \choose 0} (4x)^3 + {3 \choose 1} (4x)^2 (-1) + {3 \choose 2} (4x)(-1)^2 + {3 \choose 3}(-1)^3 = 64x^3 - 48x^2 + 12x - 1
2Step 2: Expanding the second term
Expand by the same procedure, \( -2 \left(4x - 1\right)^4 = -2\left( {4 \choose 0} (4x)^4 + {4 \choose 1} (4x)^3 (-1) + {4 \choose 2} (4x)^2 (-1)^2 + {4 \choose 3}(4x)(-1)^3 + {4 \choose 4} (-1)^4 \right) = -512x^4 + 512x^3 - 192x^2 + 32x - 2
3Step 3: Completing the Simplification
Combine the results from step 1 and step 2 to complete the simplified form of the original expression: \( 64x^3 - 48x^2 + 12x - 1 - 512x^4 + 512x^3 - 192x^2 + 32x - 2 \) which simplifies to \( -512x^4 + (64+512)x^3 + (-48-192)x^2 + (12+32)x - 1 - 2\). Hence, the simplified form of the original expression is \( -512x^4 + 576x^3 - 240x^2 + 44x - 3 \).
Key Concepts
Binomial CoefficientPolynomial ExpansionSimplification
Binomial Coefficient
The concept of the binomial coefficient is at the heart of the Binomial Theorem. When you want to expand an expression like \((a + b)^n\), the coefficients of the terms in the expansion are determined using binomial coefficients. These coefficients are represented as \({n \choose k}\), and they are calculated using a factorial formula: \({n \choose k} = \frac{n!}{k!(n-k)!}\).
Think of these coefficients as the multipliers that define how each part of the expansion should "weight" the terms involved. In our example, the expression \((4x - 1)^3\) was expanded using binomial coefficients such as \({3 \choose 0}\), \({3 \choose 1}\), \({3 \choose 2}\), and \({3 \choose 3}\).
Each coefficient is derived based on the number of ways to choose a given number of elements (k) from a set of n elements without regard to order. This provides a way to evenly distribute different combinations of terms in a polynomial expansion.
Think of these coefficients as the multipliers that define how each part of the expansion should "weight" the terms involved. In our example, the expression \((4x - 1)^3\) was expanded using binomial coefficients such as \({3 \choose 0}\), \({3 \choose 1}\), \({3 \choose 2}\), and \({3 \choose 3}\).
Each coefficient is derived based on the number of ways to choose a given number of elements (k) from a set of n elements without regard to order. This provides a way to evenly distribute different combinations of terms in a polynomial expansion.
Polynomial Expansion
Polynomial expansion involves expressing a power of a binomial as a sum of multiple terms. This is achieved through the application of the Binomial Theorem, which states that \((a + b)^n = \sum_{k=0}^{n} {n \choose k} a^{n-k} b^k\).
In our example, expanding \((4x - 1)^3\) meant distributing it into simpler terms using the formula above:
In our example, expanding \((4x - 1)^3\) meant distributing it into simpler terms using the formula above:
- The first term, \(64x^3\), came from \(({3 \choose 0})(4x)^3(-1)^0\).
- Next, \(-48x^2\) resulted from \(({3 \choose 1})(4x)^2(-1)^1\).
- The term \(12x\) came from \(({3 \choose 2})(4x)(-1)^2\).
- The final constant term \(-1\) was derived from \(({3 \choose 3})(-1)^3\).
Simplification
Simplification is the process of combining and reducing the terms in an expression to its simplest form. Once each binomial part is expanded, as we did with \((4x - 1)^3\) and \((4x - 1)^4\), it's time to gather like terms.
The expanded expressions were:
By adding the coefficients of \(x^3, x^2, x\), and constant terms, the final simplified form of the original expression was reached:
The expanded expressions were:
- \((4x - 1)^3 = 64x^3 - 48x^2 + 12x - 1\)
- \(-2(4x - 1)^4 = -512x^4 + 512x^3 - 192x^2 + 32x - 2\)
By adding the coefficients of \(x^3, x^2, x\), and constant terms, the final simplified form of the original expression was reached:
- \(-512x^4\) from the second expansion term alone.
- \((64+512)x^3\) becomes \(576x^3\).
- Adding \(-48x^2\) and \(-192x^2\) gives \(-240x^2\).
- The terms \(12x\) and \(32x\) add up to \(44x\).
- The constant terms \(-1 - 2\) simplify to \(-3\).
Other exercises in this chapter
Problem 40
In Exercises 39 - 42, you are given the probability that an event will not happen. Find the probability that the event will happen. \( P(E') = 0.92 \)
View solution Problem 40
In how many ways can six people sit in a six-passenger car?
View solution Problem 40
In Exercises 25 - 30, prove the inequality for the indicated integer values of \( n \). A factor of \( \left(2^{2n + 1} + 1\right) \) is \( 3 \).
View solution Problem 40
In Exercises 35 - 44, write an expression for the \( n \)th term of the geometric sequence. Then find the indicated term. \( a_1 = 1, r = e^{-x}, n = 4 \)
View solution