Problem 40
Question
denominators are opposites, or additive inverses. Add or subtract as indicated. Simplify the result, if possible. $$\frac{6}{x-5}+\frac{2}{5-x}$$
Step-by-Step Solution
Verified Answer
The simplified form of the given expression is \(\frac{4}{x-5}\).
1Step 1: Recognizing the Additive Inverses
The term \(x-5\) and \(5-x\) are additive inverses. We can rewrite \(5-x\) as \(-(x-5)\).
2Step 2: Rewrite Equation with Common Denominator
We rewrite the fractions by treating \(x-5\) and \(-(x-5)\) as the same denominator. So, the expression evolves as follows: \(\frac{6}{x-5} - \frac{2}{x-5}\).
3Step 3: Add the Fractions
Since they have the same denominator now, we can add the fractions: \(\frac{6-2}{x-5} = \frac{4}{x-5}\).
Key Concepts
Additive InversesCommon DenominatorSimplifying Fractions
Additive Inverses
The concept of additive inverses is foundational in understanding how to manipulate and simplify expressions, especially with variables. Additive inverses are pairs of numbers or expressions that sum up to zero. For example, in the expression from the exercise: \
Notice that \(5-x\) can be rewritten as \\[\-(x-5)\\] \This transformation highlights the additive inverse nature, allowing us to manipulate and simplify the expression more easily. Remember, understanding additive inverses helps solve equations and simplify fractions by recognizing symmetrical terms that can be canceled out.
- The terms \((x-5)\) and \((5-x)\) are additive inverses.
- When these expressions are added, their sum is zero.
Notice that \(5-x\) can be rewritten as \\[\-(x-5)\\] \This transformation highlights the additive inverse nature, allowing us to manipulate and simplify the expression more easily. Remember, understanding additive inverses helps solve equations and simplify fractions by recognizing symmetrical terms that can be canceled out.
Common Denominator
Resolving expressions with fractions often requires rewriting them with a common denominator. A common denominator is a shared multiple of the denominators of two or more fractions, enabling them to be combined. In the given exercise, the terms \((x-5)\) and \\[-(x-5)\] \serve as a common denominator by recognizing them as identical in value once the inverse is considered.
When you rewrite the fractions as: \
When you rewrite the fractions as: \
- \((x-5)\) replaces both denominators, recognizing the equivalence.
- You express \(\frac{6}{x-5} - \frac{2}{x-5}\) with one denominator.
Simplifying Fractions
Simplifying fractions is an essential skill that involves reducing the fractions to their simplest form, where the numerator and denominator have no common factors other than 1. Once fractions have a common denominator, simplification is straightforward.
In the exercise, after establishing \((x-5)\) as the common denominator, the expression simplifies from:\[\\frac{6}{x-5} - \frac{2}{x-5} = \frac{6-2}{x-5} = \frac{4}{x-5}\\] Rather than dealing with two separate fractions, you are left with one that is easy to manage.
For complete simplification:
In the exercise, after establishing \((x-5)\) as the common denominator, the expression simplifies from:\[\\frac{6}{x-5} - \frac{2}{x-5} = \frac{6-2}{x-5} = \frac{4}{x-5}\\] Rather than dealing with two separate fractions, you are left with one that is easy to manage.
For complete simplification:
- Ensure the numerator is in its simplest form. Subtract similar terms when possible.
- Check for further potential reductions between new numerators and denominators.
Other exercises in this chapter
Problem 39
Divide as indicated. $$\frac{x+1}{3} \div \frac{3 x+3}{7}$$
View solution Problem 39
Solve each rational equation. $$\frac{x+1}{3 x+9}+\frac{x}{2 x+6}=\frac{2}{4 x+12}$$
View solution Problem 40
Describe how to identify the corresponding sides in similar triangles.
View solution Problem 40
$$\text { Simplify: }(-2)^{5}-(-1)^{3}$$
View solution