Problem 39
Question
Solve each rational equation. $$\frac{x+1}{3 x+9}+\frac{x}{2 x+6}=\frac{2}{4 x+12}$$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x = 0.2\).
1Step 1: Simplify the Equation
Notice that each of the denominators, \(3x + 9\), \(2x + 6\), and \(4x + 12\), are multiples of \(x + 3\). So they can be simplified: \[\frac{x+1}{3(x + 3)}+\frac{x}{2(x + 3)}=\frac{2}{4(x + 3)}\]which can be further simplified to:\[\frac{x+1}{3}+\frac{x}{2}=\frac{2}{4}\]
2Step 2: Find the least common denominator (LCD)
The denominators are now 3, 2, and 4. The least common denominator of these is 12.
3Step 3: Multiply each term by the LCD
Do this to get rid of the fractions:\[(x+1) * 4 + x * 6 = 2 * 3\]
4Step 4: Solve the resulting equation
We now have a simple linear equation, which we can solve for \(x\):\[4x + 4 + 6x = 6\]Combine like terms:\[10x + 4 = 6\]Subtract 4 from both sides:\[10x = 2\]Finally, divide both sides by 10 to solve for \(x\):\[x = \frac{2}{10} = 0.2\]
Key Concepts
Understanding the Least Common DenominatorSimplification of FractionsSolving Linear Equations
Understanding the Least Common Denominator
When dealing with rational equations, finding the least common denominator (LCD) is a crucial step. The LCD is the smallest number that all denominators can divide into without leaving a remainder. This concept is similar to finding the least common multiple but focuses solely on denominators.
To find the LCD in our problem, we start by identifying the current denominators of the simplified equation: 3, 2, and 4. The goal is to determine the smallest number that each of these can divide by evenly.
Here's a quick tip to find the LCD:
To find the LCD in our problem, we start by identifying the current denominators of the simplified equation: 3, 2, and 4. The goal is to determine the smallest number that each of these can divide by evenly.
Here's a quick tip to find the LCD:
- List the multiples of each denominator.
- Look for the smallest common multiple among them.
Simplification of Fractions
Simplifying fractions is an important precursor to solving equations efficiently. This involves reducing fractions to their simplest form, by finding a common factor in the numerator and the denominator and dividing each by this number.
In the given exercise, the denominators were initially expressions: \(3x + 9\), \(2x + 6\), and \(4x + 12\). Each can be factored further:
In the given exercise, the denominators were initially expressions: \(3x + 9\), \(2x + 6\), and \(4x + 12\). Each can be factored further:
- \(3x + 9 = 3(x + 3)\)
- \(2x + 6 = 2(x + 3)\)
- \(4x + 12 = 4(x + 3)\)
Solving Linear Equations
Once the rational equation is free of fractions, the path to solving it becomes clearer. You're left with an equation that's linear, meaning it takes the form \(ax + b = c\), where the solution is a single value for \(x\).
After clearing the fractions by multiplying each term by the LCD (in our case, 12), you get:\[(x+1) \times 4 + x \times 6 = 2 \times 3\]This simplifies further to a linear equation:\[4x + 4 + 6x = 6\]Combine like terms (\(4x + 6x\)) to get \(10x\) plus 4:\[10x + 4 = 6\]
Now, isolate \(x\) by moving the constant term (4) to the other side:\[10x = 2\]Then, divide by 10 to solve for \(x\):\[x = \frac{2}{10} = 0.2\]With practice, solving linear equations becomes straightforward, leading to solutions that satisfy the original rational equation.
After clearing the fractions by multiplying each term by the LCD (in our case, 12), you get:\[(x+1) \times 4 + x \times 6 = 2 \times 3\]This simplifies further to a linear equation:\[4x + 4 + 6x = 6\]Combine like terms (\(4x + 6x\)) to get \(10x\) plus 4:\[10x + 4 = 6\]
Now, isolate \(x\) by moving the constant term (4) to the other side:\[10x = 2\]Then, divide by 10 to solve for \(x\):\[x = \frac{2}{10} = 0.2\]With practice, solving linear equations becomes straightforward, leading to solutions that satisfy the original rational equation.
Other exercises in this chapter
Problem 39
Add or subtract as indicated. Simplify the result, if possible. $$\frac{2 x}{x^{2}-16}+\frac{x}{x-4}$$
View solution Problem 39
Divide as indicated. $$\frac{x+1}{3} \div \frac{3 x+3}{7}$$
View solution Problem 40
denominators are opposites, or additive inverses. Add or subtract as indicated. Simplify the result, if possible. $$\frac{6}{x-5}+\frac{2}{5-x}$$
View solution Problem 40
Describe how to identify the corresponding sides in similar triangles.
View solution