Problem 40
Question
Complete the identity. $$\csc \theta=\frac{1}{\square}$$
Step-by-Step Solution
Verified Answer
The function that completes the identity is 'sin θ'. So, \(\csc \theta = \frac{1}{\sin \theta}\)
1Step 1: Identify the Trigonometric Problem
We examine the given expression: \(\csc \theta=\frac{1}{\square}\).
2Step 2: Apply Trigonometric Identities
We apply the relevant trigonometric identities, definitions, or formulas to solve the problem.
3Step 3: Simplify and Compute
We simplify the expression using known values and identities.
4Step 4: State the Result
The function that completes the identity is 'sin θ'. So, \(\csc \theta = \frac{1}{\sin \theta}\)
Key Concepts
Cosecant functionReciprocal identitiesSine function
Cosecant function
The cosecant function, denoted as \( \csc \theta \), is an important concept in trigonometry. It is defined as the reciprocal of the sine function, which means it is the opposite or inverse in the context of multiplication. If you know the sine of an angle, you can easily find its cosecant by using the formula:
While the sine function measures how far up or down a point is on the unit circle, the cosecant relates the same point to its height in much larger arcs or circles. Remember, \( \csc \theta \) can never be zero, because this would require division by zero (which is undefined in mathematics). Understanding and using the cosecant function can greatly simplify working with trigonometric expressions, especially when inverse relationships are involved.
- \( \csc \theta = \frac{1}{\sin \theta} \)
While the sine function measures how far up or down a point is on the unit circle, the cosecant relates the same point to its height in much larger arcs or circles. Remember, \( \csc \theta \) can never be zero, because this would require division by zero (which is undefined in mathematics). Understanding and using the cosecant function can greatly simplify working with trigonometric expressions, especially when inverse relationships are involved.
Reciprocal identities
Reciprocal identities are a fundamental part of trigonometry. They relate each trigonometric function to its reciprocal counterpart, allowing us to express a function in terms of its reciprocal. These identities help in simplifying complex expressions and solving trigonometric equations. In the case of the cosecant function, it has a reciprocal identity involving the sine function:
It is also crucial for proving other trigonometric identities and during integration, where reciprocal functions often appear. Understanding the concept of reciprocals expands your ability to maneuver through mathematical problems systematically.
- \( \csc \theta = \frac{1}{\sin \theta} \)
It is also crucial for proving other trigonometric identities and during integration, where reciprocal functions often appear. Understanding the concept of reciprocals expands your ability to maneuver through mathematical problems systematically.
Sine function
The sine function, written as \( \sin \theta \), is one of the basic trigonometric functions that measures the vertical position of a point as it traces a circle. In a unit circle, it is the coordinate of the point vertically above or below the x-axis. The sine function is periodic and oscillates between -1 and 1.
- \( \sin \theta = \text{opposite side} / \text{hypotenuse} \)
- If \( \sin \theta = x \), then \( \csc \theta = \frac{1}{x} \)
Other exercises in this chapter
Problem 39
Use a graphing utility to graph \(f\) and \(g\) in the same viewing window. (Include two full periods.) Make a conjecture about the functions. $$\begin{aligned}
View solution Problem 39
Use the angle-conversion capabilities of a graphing utility to convert the angle measure to \(\mathbf{D}^{\circ} \mathbf{M}^{\prime} \mathbf{S}^{\prime \prime}\
View solution Problem 40
Compare the graph of the function with the graph of \(f(x)=\arccos x\) \(g(x)=\arccos (-x)-3\)
View solution Problem 40
Use a graphing utility to graph \(f\) and \(g\) in the same viewing window. (Include two full periods.) Make a conjecture about the functions. $$\begin{aligned}
View solution