Problem 39
Question
Use a graphing utility to graph \(f\) and \(g\) in the same viewing window. (Include two full periods.) Make a conjecture about the functions. $$\begin{aligned} &f(x)=\sin x\\\ &g(x)=\cos \left(x-\frac{\pi}{2}\right) \end{aligned}$$
Step-by-Step Solution
Verified Answer
After graphing both functions, we can conjecture that \(f(x)=\sin{x}\) and \(g(x)=\cos{\left(x-\frac{\pi}{2}\right)}\) are equivalent as they both have the same shape, period, and the latter is shifted \(\frac{\pi}{2}\) to the right of the former.
1Step 1: Graph the function \(f(x)=\sin{x}\)
Identify the period of the sine function, which is \(2\pi\). Mark points at intervals corresponding to the period and plot the function for a complete cycle showing two full periods.
2Step 2: Graph the function \(g(x)=\cos{\left(x-\frac{\pi}{2}\right)}\)
Identify the period of the cosine function which is \(2\pi\). However, this function has a phase shift of \(\frac{\pi}{2}\) to the right. Mark and plot points for the cosine function taking the phase shift into account. Again, draw the graph showing two full periods.
3Step 3: Make a conjecture
Once both functions have been graphed, compare the two graphs. Look at their shapes, periods, and starting points.
Key Concepts
Sine FunctionCosine FunctionPhase ShiftGraphing Trigonometric Functions
Sine Function
The sine function, represented as \( f(x) = \sin{x} \), is a trigonometric function that describes a smooth, wave-like pattern. It is a periodic function, meaning it repeats its values in regular intervals. The period of the sine function is \( 2\pi \), which signifies the length of one complete cycle of the wave. To graph sine, start at the origin (0,0), rise to a peak at \( \pi/2 \), return to the axis at \( \pi \), reach the lowest point at \( 3\pi/2 \), and then return to the axis at \( 2\pi \). This pattern then repeats. Here are some key features:
- Amplitude: The maximum height of the wave from the origin, usually 1.
- Phase Shift: For purely \( \sin x \), it starts at the origin with no shift.
- Vertical Shift: None in the basic sine function, but it can be shifted by adding a constant.
Cosine Function
The cosine function, denoted by \( f(x) = \cos{x} \), is another fundamental trigonometric function. Similar to sine, it is also periodic with the same period of \( 2\pi \). However, unlike the sine function, cosine starts at its maximum value. For a basic graph of the cosine function:
- Start at the peak (1) at \( x = 0 \).
- Cross the axis at \( \pi/2 \).
- Reach the minimum (-1) at \( \pi \).
- Return to zero at \( 3\pi/2 \).
- Complete the cycle back to the peak at \( 2\pi \).
- Amplitude: Like sine, typically 1.
- Phase Shift: Begins at a maximum, unlike sine which starts at zero.
- Vertical Shift: None, unless altered by adding a constant.
Phase Shift
A phase shift refers to the horizontal movement of a periodic function on the coordinate plane. For trigonometric functions like sine and cosine, phase shifts alter the position of the start of the cycle. A function \( g(x) = \cos{(x - \frac{\pi}{2})} \) illustrates a phase shift:
- Right Shift: \( -\frac{\pi}{2} \) moves cosine function to the right by \( \frac{\pi}{2} \).
- It affects when the peaks, troughs, and zero-crossings occur.
- Formula: Generally expressed as \( f(x) = \cos{(x - c)} \), shifting right if \( c > 0 \).
Graphing Trigonometric Functions
Graphing trigonometric functions like sine and cosine is a vital skill in understanding oscillatory behavior. When graphing, consider:
- Amplitude: Height of the wave, affecting its vertical stretch.
- Period: Length of one complete cycle, traditionally \( 2\pi \) for both sine and cosine.
- Phase Shift: Horizontal shift of the graph, changing where the cycle starts.
- Vertical Shift: Moves the graph up or down without altering its shape.
Other exercises in this chapter
Problem 38
Sketch the graphs of \(f\) and \(g\) in the same coordinate plane. (Include two full periods.) $$\begin{aligned} &f(x)=2 \cos 2 x\\\ &g(x)=-\cos 4 x \end{aligne
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A park is showing a movie on the lawn. The base of the screen is 6 feet off the ground and the screen is 22 feet high. (See figure.) (a) Find the angles of elev
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Use the angle-conversion capabilities of a graphing utility to convert the angle measure to \(\mathbf{D}^{\circ} \mathbf{M}^{\prime} \mathbf{S}^{\prime \prime}\
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Complete the identity. $$\csc \theta=\frac{1}{\square}$$
View solution