Problem 40
Question
\(23-48\) Solve the inequality. Express the answer using interval notation. $$ 3-|2 x+4| \leq 1 $$
Step-by-Step Solution
Verified Answer
The solution is \(( -\infty, -3 ] \cup [ -1, \infty )\).
1Step 1: Isolate Absolute Value
The inequality is \(3 - |2x + 4| \leq 1\). Start by isolating the absolute value expression: subtract 3 from both sides to get \(-|2x + 4| \leq -2\). Multiply every term by -1 to obtain \(|2x + 4| \geq 2\), remembering to reverse the inequality sign when multiplying by a negative number.
2Step 2: Remove Absolute Value
The inequality \(|2x + 4| \geq 2\) means that the expression inside the absolute value could be either greater than or equal to 2 or less than or equal to -2. So, split into two inequalities: \(2x + 4 \geq 2\) and \(2x + 4 \leq -2\).
3Step 3: Solve First Inequality
Solve \(2x + 4 \geq 2\) by subtracting 4 from both sides: \(2x \geq -2\). Then, divide both sides by 2 to get \(x \geq -1\).
4Step 4: Solve Second Inequality
Solve \(2x + 4 \leq -2\) by subtracting 4 from both sides: \(2x \leq -6\). Then, divide both sides by 2 to get \(x \leq -3\).
5Step 5: Combine Solutions
The solutions \(x \geq -1\) and \(x \leq -3\) are combined because \(|2x + 4| \geq 2\) indicates the values of \(x\) fall outside the range between these numbers. Therefore, the interval notation solution is \(( -\infty, -3 ] \cup [ -1, \infty )\).
Key Concepts
Absolute Value InequalitiesInterval NotationInequality Solution Steps
Absolute Value Inequalities
Absolute value inequalities can seem challenging at first, but with a clear understanding of the concept, they become much easier to handle. Absolute value refers to the distance of a number from zero on the number line, regardless of direction. Therefore, absolute value inequalities involve expressions within absolute value bars that need to satisfy a certain condition.
When you face an absolute value inequality like \(|a| \geq b\), it implies the expression inside the absolute value can be either greater than or equal to \(b\) or less than or equal to \(-b\). This is due to the nature of absolute value capturing two possible scenarios on the number line:
When you face an absolute value inequality like \(|a| \geq b\), it implies the expression inside the absolute value can be either greater than or equal to \(b\) or less than or equal to \(-b\). This is due to the nature of absolute value capturing two possible scenarios on the number line:
- One where the expression is a positive distance (\(a \geq b\)).
- Another where it is a negative distance towards zero (\(a \leq -b\)).
Interval Notation
Interval notation is a helpful way to express the range of solutions for inequalities in a concise form. It provides a clear visual of the solution set that can be easily understood. This notation uses brackets and parentheses:
In the provided exercise, the interval notation \((-\infty, -3] \cup [-1, \infty)\) expresses two separate ranges - the first interval representing all values from \(-\infty\) to \(-3\) (including \(-3\)), and the second covering values from \(-1\) to \(\infty\), starting at \(-1\). The union sign \(\cup\) is used to combine these intervals, showing that either range is part of the solution.
- Square brackets \([\, ]\) indicate that an endpoint is included in the solution (\(\leq\) or \(\geq\)).
- Parentheses \((\, )\) denote that the endpoint is not included (\(<\) or \(>\)).
In the provided exercise, the interval notation \((-\infty, -3] \cup [-1, \infty)\) expresses two separate ranges - the first interval representing all values from \(-\infty\) to \(-3\) (including \(-3\)), and the second covering values from \(-1\) to \(\infty\), starting at \(-1\). The union sign \(\cup\) is used to combine these intervals, showing that either range is part of the solution.
Inequality Solution Steps
Solving inequalities is a systematic endeavor. Let's break down the steps used in our example to solve an absolute value inequality. The process can generally be structured as follows:
- **Isolate the Absolute Value**: Begin by isolating the absolute value on one side of the inequality. This involves rearranging the inequality if necessary, such as adding or subtracting terms from both sides.
- **Flip and Split**: Once isolated, interpret the absolute value inequality by reversing and creating two separate inequalities. Remember, multiplying through by a negative number reverses the inequality sign.
- **Solve Each Inequality**: Work through each of the simpler inequalities independently. Use basic algebraic manipulation like adding, subtracting, multiplying, or dividing to find the solution sets for each.
- **Combine Solutions**: Finally, evaluate whether to union the solutions, which means joining different solution sets using the union symbol \(\cup\), particularly when dealing with absolute value inequalities that create non-overlapping solution regions.
Other exercises in this chapter
Problem 39
The given equation is either linear or equivalent to a linear equation. Solve the equation. \(\frac{3}{x+1}-\frac{1}{2}=\frac{1}{3 x+3}\)
View solution Problem 40
Evaluate the expression and write the result in the form a bi. $$ \frac{25}{4-3 i} $$
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Solve the nonlinear inequality. Express the solution using interval notation and graph the solution set. $$ x^{2}+5 x+6>0 $$
View solution Problem 40
Find all real solutions of the equation. $$ x^{2}-6 x+1=0 $$
View solution