Problem 4
Question
Write an equation of an ellipse in standard form with center at the origin and with the given vertex and co-vertex. $$ (0,6),(1,0) $$
Step-by-Step Solution
Verified Answer
The standard form equation of the ellipse is \(x^2+ \frac{y^2}{36}=1\).
1Step 1: Determine the value of 'a'
The value of 'a' corresponds to the distance from the center to a vertex along the major axis. Since the given vertex is (0,6), the distance from the center to the vertex, which is 'a', will be 6.
2Step 2: Determine the value of 'b'
The value of 'b' is the distance from the center to a co-vertex along the minor axis. Given that the co-vertex is (1,0), the distance from the origin to the co-vertex, which is 'b', will be 1.
3Step 3: Write the equation of the ellipse
Substituting the values of 'a' and 'b' into the standard form of the equation of an ellipse, the equation becomes \(\frac{x^2}{1^2}+\frac{y^2}{6^2}=1\), which simplifies to \(x^2+ \frac{y^2}{36}=1\).
Key Concepts
Ellipse Standard FormMajor and Minor AxesVertices and Co-Vertices
Ellipse Standard Form
An ellipse is a geometric shape that looks like a stretched circle. To describe it mathematically, we use an equation called the "ellipse standard form." The standard form of an ellipse equation is written as: \[\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\] In this equation, 'a' and 'b' are crucial values that define the ellipse's shape and size. Here is how you can think about the parts:
- \(x\) and \(y\) represent any point on the ellipse.
- \(a\) is the length from the center of the ellipse to a vertex on the horizontal axis, also known as the semi-major axis.
- \(b\) is the length from the center to a co-vertex on the vertical axis, known as the semi-minor axis.
- "1" on the right side of the equation ensures the total shape remains consistent as an ellipse.
Major and Minor Axes
The major and minor axes are lines that describe the main directions and dimensions of an ellipse. Understanding them is key to working with ellipses effectively.
- Major Axis: The longest line that runs through the center of the ellipse. The vertices lie on this axis, and its total length is equal to twice the value of 'a' (i.e., \(2a\)). For example, in the ellipse given in our exercise, if 'a' is 6, then the major axis is 12 units long.
- Minor Axis: The shortest line through the center of the ellipse. This axis runs perpendicular to the major axis. The co-vertices lie on the minor axis, and its total length is twice the value of 'b' (i.e., \(2b\)). For the exercise, if 'b' is 1, the minor axis is 2 units long.
Vertices and Co-Vertices
The vertices and co-vertices are significant points on the ellipse that help define its shape. Here's how to locate and interpret them:
- Vertices: These are the points of intersection of the ellipse with its major axis. Since the major axis is the longer axis, vertices are the farthest points from the center. In our example, the given vertex is at \((0,6)\). This point specifies that 'a' is 6.
- Co-Vertices: Located at the ends of the minor axis, these points are closer to the center than the vertices. In our exercise, the co-vertex \((1,0)\) indicates that 'b' is 1.
Other exercises in this chapter
Problem 3
Graph each equation. Identify the conic section and describe the graph and its lines of symmetry. Then find the domain and range. $$ x^{2}+y^{2}=16 $$
View solution Problem 3
Write an equation of a circle with the given center and radius. Check your answers. $$ (2,3), 4.5 $$
View solution Problem 4
Write an equation of an ellipse with the given characteristics. Check your answers. center \((3,-6),\) vertical major axis of length \(14,\) minor axis of lengt
View solution Problem 4
Write an equation for a graph that is the set of all points in the plane that are equidistant from the given point and the given line. $$ F(0,-8), y=8 $$
View solution