Problem 4
Question
Write an equation for a graph that is the set of all points in the plane that are equidistant from the given point and the given line. $$ F(0,-8), y=8 $$
Step-by-Step Solution
Verified Answer
The equation of the graph that represents all points in the plane that are equidistant from the given point F(0,-8) and the given line y=8, is given by \(x^2=32y\).
1Step 1: Determine the vertex
The vertex of the parabola is halfway between the focus F(0,-8) and the directrix y=8. Therefore, the vertex coordinates will be given by (0, average between -8 and 8), or (0,0).
2Step 2: Calculate the value of p
The value p is the distance from the vertex to the focus or the directrix. The distance from the vertex (0,0) to the focus (0,-8) is 8 units. So, p equals to 8.
3Step 3: Write the equation of the parabola
The general equation for a parabola opening upwards (as it's the case here) is: \((x-h)^2=4p(y-k)\). Substitute h=0, k=0 and p=8 in the equation and it becomes \(x^2=32y\).
Key Concepts
Focus and DirectrixDistance FormulaVertex of Parabola
Focus and Directrix
When studying parabolas, a crucial concept to grasp is the focus and directrix. These two elements define the parabola's shape and orientation in the plane. The **focus** is a fixed point, while the **directrix** is a fixed line. Each point on the parabola is equidistant to the focus and the directrix.
This balance of distances is vital because it is by this property that parabolas are constructed. For example, if you have a focus **F(0, -8)** and a directrix **y = 8**, the set of all points that maintain this equidistant nature will form a parabola.
In summary:
This balance of distances is vital because it is by this property that parabolas are constructed. For example, if you have a focus **F(0, -8)** and a directrix **y = 8**, the set of all points that maintain this equidistant nature will form a parabola.
In summary:
- Focus: A special point acting as a fixed distance reference
- Directrix: A line serving as another fixed distance reference
Distance Formula
To determine the points on a parabola, we need to understand how to measure distances in the plane. The **distance formula** is a powerful tool for this. It calculates the distance between two points ( \(x_1, y_1\) and \(x_2, y_2\) ) in the 2-dimensional plane and is given by:\[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]
This formula allows us to find how far any point is from the focus and the directrix. For example, take the vertex at (0, 0), the focus at (0, -8), and the directrix **y = 8**. We can use the distance formula to assert that a point on the parabola is equidistant from both the focus and the directrix.
This understanding is crucial for calculating the vertex and writing the equation of a parabola. It helps confirm equal distances from the specific points and lines that define the parabolic shape.
This formula allows us to find how far any point is from the focus and the directrix. For example, take the vertex at (0, 0), the focus at (0, -8), and the directrix **y = 8**. We can use the distance formula to assert that a point on the parabola is equidistant from both the focus and the directrix.
This understanding is crucial for calculating the vertex and writing the equation of a parabola. It helps confirm equal distances from the specific points and lines that define the parabolic shape.
Vertex of Parabola
The **vertex of a parabola** is a key point that helps in constructing its equation. It is located exactly halfway between the focus and the directrix.
To find the vertex, you calculate the midpoint between the y-coordinate of the focus and the directrix. For instance, with a focus at **(0, -8)** and a directrix at **y = 8**, the vertex will be located at the average of the two: **(0, 0)**. This is derived by computing the midpoint:\[y_{vertex} = \frac{-8 + 8}{2} = 0\]
The vertex is essential as it serves as the point around which the parabola is symmetric. This location is used to determine the general form of the parabola's equation. In an upward-opening parabola, this form is:\[(x-h)^2 = 4p(y-k)\]
where \(h\) and \(k\) are the coordinates of the vertex.
To find the vertex, you calculate the midpoint between the y-coordinate of the focus and the directrix. For instance, with a focus at **(0, -8)** and a directrix at **y = 8**, the vertex will be located at the average of the two: **(0, 0)**. This is derived by computing the midpoint:\[y_{vertex} = \frac{-8 + 8}{2} = 0\]
The vertex is essential as it serves as the point around which the parabola is symmetric. This location is used to determine the general form of the parabola's equation. In an upward-opening parabola, this form is:\[(x-h)^2 = 4p(y-k)\]
where \(h\) and \(k\) are the coordinates of the vertex.
- Vertex: (0, 0) for the given example
- Equation form: Anchored by the positions of the vertex, focus, and directrix
Other exercises in this chapter
Problem 4
Write an equation of an ellipse in standard form with center at the origin and with the given vertex and co-vertex. $$ (0,6),(1,0) $$
View solution Problem 4
Write an equation of an ellipse with the given characteristics. Check your answers. center \((3,-6),\) vertical major axis of length \(14,\) minor axis of lengt
View solution Problem 4
Graph each equation. $$ x^{2}-4 y^{2}=4 $$
View solution Problem 4
Graph each equation. Identify the conic section and describe the graph and its lines of symmetry. Then find the domain and range. $$ 3 y^{2}-x^{2}=9 $$
View solution