Problem 4
Question
Graph each function. Do not use a calculator. $$f(x)=\left(\frac{1}{4}\right)^{x}$$
Step-by-Step Solution
Verified Answer
The function \( f(x) = \left(\frac{1}{4}\right)^{x} \) is a decreasing exponential graph, crossing the y-axis at (0, 1) and approaching the x-axis as \( x \) increases.
1Step 1: Determine the Base of the Exponential Function
In the given function, \( f(x) = \left(\frac{1}{4}\right)^x \), the base is \( \frac{1}{4} \). This is important because it tells us how the function behaves. Since the base is between 0 and 1, the function will be decreasing; as \( x \) increases, \( f(x) \) decreases.
2Step 2: Understand the Key Features
For exponential functions of the form \( a^x \), where \( 0 < a < 1 \), the graph passes through the point (0, 1) because any number raised to the power of 0 is 1. As \( x \to \infty \), \( f(x) \to 0 \), and as \( x \to -\infty \), \( f(x) \to \infty \). The function never actually touches the x-axis, so the x-axis is a horizontal asymptote.
3Step 3: Calculate Key Points
Evaluate the function at some key values to help sketch the graph. For instance, - At \( x = 0 \), \( f(0) = \left( \frac{1}{4} \right)^0 = 1 \).- At \( x = 1 \), \( f(1) = \left( \frac{1}{4} \right)^1 = \frac{1}{4} \).- At \( x = 2 \), \( f(2) = \left( \frac{1}{4} \right)^2 = \frac{1}{16} \).- At \( x = -1 \), \( f(-1) = \left( \frac{1}{4} \right)^{-1} = 4 \).
4Step 4: Plot the Points
Using the calculated values, plot the points (0, 1), (1, \( \frac{1}{4} \)), (2, \( \frac{1}{16} \)), and (-1, 4) on a coordinate plane. These points will guide the shape of the graph as it decreases from left to right.
5Step 5: Draw the Graph
Connect the plotted points with a smooth curve. Ensure the curve approaches the x-axis as \( x \to \infty \), reflecting the horizontal asymptote. The curve should rise steeply as \( x \to -\infty \). This gives the overall shape of the decreasing exponential graph.
Key Concepts
GraphingBase of Exponential FunctionHorizontal Asymptote
Graphing
Graphing exponential functions can be an exciting journey if you understand the basic properties that define their shape. The given function is a classic example of an exponential one:
- The base determines the behavior of the graph and whether it increases or decreases.
- The intercept and direction are crucial for sketching without calculators.
- \( x = 0 \Rightarrow f(0) = 1 \)
- \( x = 1 \Rightarrow f(1) = \frac{1}{4} \)
- \( x = 2 \Rightarrow f(2) = \frac{1}{16} \)
- \( x = -1 \Rightarrow f(-1) = 4 \)
- Approach the x-axis as \( x \to \infty \).
- Curve upwards steeply as \( x \to -\infty \).
Base of Exponential Function
The base in an exponential function like \( f(x) = a^x \) is pivotal because it dictates how the function behaves. Here, \( a = \frac{1}{4} \). This number tells us that the graph will decrease because:
- The base is between 0 and 1.
- Each additional unit increase in \( x \) results in a smaller fraction for \( f(x) \).
Horizontal Asymptote
A horizontal asymptote in exponential functions serves as an invisible boundary that the graph approaches but never crosses. For the function \( f(x) = \left(\frac{1}{4}\right)^x \), the x-axis itself is the horizontal asymptote.This occurs because:
- As \( x \to \infty \), \( f(x) \to 0 \).
- The function values keep getting smaller but will never be zero.
Other exercises in this chapter
Problem 4
Decide whether each function is one-to-one. $$f(x)=-x^{2}$$
View solution Problem 4
Solve each equation. Express all solutions in exact form. Do not use a calculator. $$5\left(10^{3 x}\right)-4=6$$
View solution Problem 5
Decide whether each function is one-to-one. $$f(x)=\sqrt{36-x^{2}}$$
View solution Problem 5
For each statement, write an equivalent statement in logarithmic form. Do not use a calculator. $$10^{-4}=0.0001$$
View solution