Problem 4
Question
Consider the general logarithmic function \(f(x)=\log _{b}(x)\). Why \(\operatorname{can}^{\prime} \mathrm{t} x\) be zero?
Step-by-Step Solution
Verified Answer
\(x\) cannot be zero in \(\log_b(x)\) because \(b^y\) is never zero for any real \(y\).
1Step 1: Understanding Logarithmic Functions
A logarithmic function is defined as \(f(x) = \log_b(x)\), where \(b\) is the base greater than zero and not equal to one, and \(x\) is the input value. The base \(b\) is a constant, while \(x\) represents the number whose logarithm is being taken.
2Step 2: Domain of Logarithmic Functions
The domain of a logarithmic function \(f(x) = \log_b(x)\) includes all positive real numbers. This is because a logarithm represents the exponent to which the base \(b\) must be raised to get \(x\), and such an exponent only exists for positive values of \(x\).
3Step 3: Analyzing Why \(x\) Cannot Be Zero
For \(x = 0\), we would need to find an exponent \(y\) such that \(b^y = 0\). However, no real number \(y\) satisfies this equation because any positive base raised to any real exponent is never zero. As a result, \(x = 0\) is not within the domain of the logarithmic function.
4Step 4: Conclusion on Valid Input Values for \(x\)
Since there is no real number exponent that can make a positive base \(b\) result in zero, \(x\) must always be greater than zero in a logarithmic function. Therefore, \(x\) cannot be zero by definition.
Key Concepts
Domain of Logarithmic FunctionsExponents and LogarithmsProperties of Logarithms
Domain of Logarithmic Functions
The domain of a logarithmic function is crucial to understanding how these functions operate. In mathematics, the domain refers to all the possible input values that will not cause the function to fail. For a general logarithmic function, expressed as \(f(x) = \log_b(x)\), the function is defined purely for positive values of \(x\).
- This is because the logarithm \(\log_b(x)\) transforms \(x\) into an exponent \(y\) such that \(b^y = x\).
- For any positive base \(b\), this process can only produce positive outcomes for \(x\), which means \(x\) must be greater than zero.
- Thus, the function does not allow for zero or negative values, as these would translate into undefined or non-real exponents.
Exponents and Logarithms
Understanding the connection between exponents and logarithms is key to unlocking their properties. Logarithms and exponents are inverse operations. The expression \(b^y = x\) is the exponential form, where \(b\) is the base, \(y\) is the exponent, and \(x\) is the result. The logarithmic form of this expression is \(y = \log_b(x)\).
- This highlights the inverse relationship where logarithms 'undo' the exponentiation.
- A logarithm answers the question: "To what exponent must the base \(b\) be raised, to yield \(x\)?"
- This means if you know the result of an exponentiation, you can find the exponent using a logarithm.
Properties of Logarithms
Logarithms come with several properties that make calculations simpler and more intuitive. Understanding these properties can greatly enhance your problem-solving skills:
- Product Rule: \(\log_b(MN) = \log_b(M) + \log_b(N)\). This property shows how a product inside the logarithm can be broken down into a sum of logs.
- Quotient Rule: \(\log_b\left(\frac{M}{N}\right) = \log_b(M) - \log_b(N)\). Division inside a log converts into a subtraction of logs.
- Power Rule: \(\log_b(M^k) = k \cdot \log_b(M)\). An exponent on the logged number becomes a multiplier in front of the log.
- Change of Base Formula: For changing the base of a logarithm, use \(\log_b(x) = \frac{\log_k(x)}{\log_k(b)}\), where \(k\) is any positive number different from 1.
Other exercises in this chapter
Problem 4
For the following exercises, use like bases to solve the exponential equation. \(4^{-3 v-2}=4^{-v}\)
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For the following exercises, expand each logarithm as much as possible. Rewrite each expression as a sum, difference, or product of logs. \(\ln (3 a b \cdot 5 c
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Discuss the meaning of the common logarithm. What is its relationship to a logarithm with base \(b\), and how does the notation differ?
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The graph of \(f(x)=\left(\frac{1}{2}\right)^{-x}\) is reflected about the \(y\) -axis and compressed vertically by a factor of \(\frac{1}{5} . \quad\) What is
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