Problem 39
Question
Simplify. $$ (1-4 i)(2+i) $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(6 - 7i\).
1Step 1: Apply the Distributive Property
To simplify the expression \[(1-4i)(2+i),\]use the distributive property (also called the FOIL method for binomials). Expand the product:\[(1)(2) + (1)(i) - (4i)(2) - (4i)(i).\]
2Step 2: Calculate Each Term
Now calculate each term separately:- For \((1)(2)\), the result is \(2\).- For \((1)(i)\), the result is \(i\).- For \((4i)(2)\), the result is \(-8i\).- For \((-4i)(i)\), since \(i^2 = -1\), the result is \(4\).
3Step 3: Combine Like Terms
Now, combine all the terms:\[2 + i - 8i + 4.\]Add the real parts and the imaginary parts separately:- Combine the real parts: \(2 + 4 = 6\).- Combine the imaginary parts: \(i - 8i = -7i\).Thus, the expression simplifies to:\[6 - 7i.\]
Key Concepts
Distributive PropertyFOIL MethodImaginary Unit
Distributive Property
The distributive property is a fundamental mathematical principle that you often use when simplifying algebraic expressions. It allows you to multiply a single term by each term in a polynomial or binomial. This principle is particularly helpful when dealing with expressions that contain variables or complex numbers.
In our example, \[(1 - 4i)(2 + i),\]the distributive property helps us break down the multiplication into more manageable parts. Essentially, it tells us to "distribute" each term from the first binomial to every term in the second binomial. This distributive action can be summarized in the steps:
In our example, \[(1 - 4i)(2 + i),\]the distributive property helps us break down the multiplication into more manageable parts. Essentially, it tells us to "distribute" each term from the first binomial to every term in the second binomial. This distributive action can be summarized in the steps:
- Multiply the first term of the first polynomial by each term of the other polynomial.
- Repeat this process with each subsequent term of the first polynomial.
FOIL Method
The FOIL method is a specific application of the distributive property tailored for multiplying two binomials—expressions with two terms each. FOIL stands for First, Outer, Inner, Last, which are the steps to follow.
Here's how it works using the expression \[(1 - 4i)(2 + i):\]
Here's how it works using the expression \[(1 - 4i)(2 + i):\]
- First: Multiply the first terms in each binomial, \(1 imes 2 = 2.\)
- Outer: Multiply the outer terms,\(1 imes i = i.\)
- Inner: Multiply the inner terms,\(-4i imes 2 = -8i.\)
- Last: Multiply the last terms,\(-4i imes i.\)
Imaginary Unit
The imaginary unit, denoted as \(i,\) is fundamental in the world of complex numbers and mathematics in general. By definition, \(i\) is the square root of \(-1,\) so \(i^2 = -1.\)
This seemingly simple idea allows mathematicians and engineers to solve equations that have no real solutions, greatly expanding the scope of mathematical problems we can tackle. In calculations, recognizing when \(i^2\) occurs helps in simplifying expressions further. For instance, in the multiplication of the expression \((-4i imes i),\) knowing that \(i^2 = -1\) turns this into:\(-4i^2\) which simplifies to \(4\) because \(-4 imes -1 = 4.\)
Hence, when working with the imaginary unit, remember that it often transforms terms significantly, switching between imaginary and real, as it brings negative signs into play. Understanding this property is key to mastering problems involving complex numbers.
This seemingly simple idea allows mathematicians and engineers to solve equations that have no real solutions, greatly expanding the scope of mathematical problems we can tackle. In calculations, recognizing when \(i^2\) occurs helps in simplifying expressions further. For instance, in the multiplication of the expression \((-4i imes i),\) knowing that \(i^2 = -1\) turns this into:\(-4i^2\) which simplifies to \(4\) because \(-4 imes -1 = 4.\)
Hence, when working with the imaginary unit, remember that it often transforms terms significantly, switching between imaginary and real, as it brings negative signs into play. Understanding this property is key to mastering problems involving complex numbers.
Other exercises in this chapter
Problem 39
Solve each inequality using a graph, a table, or algebraically. $$ 18 x-x^{2} \leq 81 $$
View solution Problem 39
Graph each function. $$ y=\frac{1}{3} x^{2}-4 x+15 $$
View solution Problem 39
Solve each equation by completing the square. \(x^{2}+8 x+9=-9\)
View solution Problem 39
Solve each equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are located. $$ 0.5 x^{2}-3=0 $$
View solution