Problem 39
Question
Find the partial sum \(S_{n}\) of the geometric sequence that satisfies the given conditions. $$ a=5, \quad r=2, \quad n=6 $$
Step-by-Step Solution
Verified Answer
The partial sum \( S_6 \) is 315.
1Step 1: Identify the Formula
To find the partial sum of a geometric sequence, we need to use the formula for the sum of the first n terms of a geometric sequence: \( S_n = a \frac{r^n - 1}{r - 1} \). Here, \( a \) is the first term, \( r \) is the common ratio, and \( n \) is the number of terms.
2Step 2: Substitute the Given Values
Substitute the given values into the formula: \( a = 5 \), \( r = 2 \), and \( n = 6 \). Thus, the formula becomes: \( S_6 = 5 \frac{2^6 - 1}{2 - 1} \).
3Step 3: Calculate \( r^n \)
Calculate \( 2^6 \). Since \( 2^6 = 64 \), plug this value back into the formula: \( S_6 = 5 \frac{64 - 1}{2 - 1} \).
4Step 4: Simplify the Formula
Simplify the terms inside the fraction: \( 64 - 1 = 63 \). Thus, the formula simplifies to \( S_6 = 5 \frac{63}{1} \).
5Step 5: Final Calculation
Since \( \frac{63}{1} = 63 \), the formula becomes \( S_6 = 5 \times 63 \). Calculate this multiplication to get \( S_6 = 315 \).
Key Concepts
Partial SumCommon RatioFirst Term
Partial Sum
The partial sum is a crucial concept in understanding sequences. In the case of a geometric sequence, the partial sum refers to the sum of a finite number of terms, denoted typically as \( S_n \). This sum provides insight into the behavior of the sequence up to the \( n \)-th term.
When working with geometric sequences, the formula for calculating the partial sum is:
When working with geometric sequences, the formula for calculating the partial sum is:
- \( S_n = a \frac{r^n - 1}{r - 1} \)
- \( a \) is the first term of the sequence,
- \( r \) is the common ratio,
- \( n \) is the number of terms you wish to sum.
Common Ratio
The common ratio, denoted as \( r \), is a fundamental component of a geometric sequence. It describes the consistent factor by which each term in the sequence is multiplied to get the next term.
In the provided exercise, the common ratio is 2, indicating each term is twice the previous one. Here's how you can identify and use the common ratio:
In the provided exercise, the common ratio is 2, indicating each term is twice the previous one. Here's how you can identify and use the common ratio:
- Look at any two consecutive terms in the sequence.
- Divide the second term by the first. For example, if the terms are 5 and 10, the ratio is \( 10/5 = 2 \).
First Term
In any sequence, the first term, denoted as \( a \), serves as the starting point. It is the foundation upon which all subsequent elements of the sequence are built.
In the geometric sequence from the exercise, the first term \( a \) is given as 5. Knowing this first term is vital because:
In the geometric sequence from the exercise, the first term \( a \) is given as 5. Knowing this first term is vital because:
- It establishes the beginning of the sequence.
- It is prominently featured in the formula for calculating the partial sum, influencing all future sums.
- It determines the scale of the sequence, influencing the magnitude of the terms.
Other exercises in this chapter
Problem 38
The first term of an arithmetic sequence is \(1,\) and the common difference is \(4 .\) Is \(11,937\) a term of this sequence? If so, which term is it?
View solution Problem 38
Find the first four partial sums and the \(n\)th partial sum of the sequence \(a_{n} .\) \(a_{n}=\log \left(\frac{n}{n+1}\right)\) [Hint: Use a property of loga
View solution Problem 39
39-44 Find the partial sum \(S_{n}\) of the arithmetic sequence that satisfies the given conditions. $$a=1, d=2, n=10$$
View solution Problem 39
Find the sum. $$\sum_{k=1}^{4} k$$
View solution