Problem 38
Question
The first term of an arithmetic sequence is \(1,\) and the common difference is \(4 .\) Is \(11,937\) a term of this sequence? If so, which term is it?
Step-by-Step Solution
Verified Answer
Yes, 11,937 is the 2,985th term of the sequence.
1Step 1: Understanding the Sequence
In an arithmetic sequence, each term after the first is obtained by adding the common difference to the previous term. Here, the first term is 1, and the common difference is 4.
2Step 2: Write the Formula for the n-th Term
The formula for the n-th term of an arithmetic sequence is given by: \( a_n = a_1 + (n-1) imes d \), where \( a_1 \) is the first term, \( n \) is the term number, and \( d \) is the common difference.
3Step 3: Substitute Known Values
Substitute the known values into the formula: \( a_n = 1 + (n-1) imes 4 \).
4Step 4: Set Up the Equation
To find if 11,937 is a term in the sequence, set \( a_n = 11,937 \) and form the equation: \[ 11,937 = 1 + (n-1) imes 4 \]
5Step 5: Solve for n
Re-arrange and solve the equation: - Subtract 1 from both sides: \( 11,936 = (n-1) imes 4 \).- Divide both sides by 4: \( 2,984 = n-1 \).- Add 1 to both sides to solve for \( n \): \( n = 2,985 \).
6Step 6: Verify the Result
Substitute \( n = 2,985 \) into the n-th term formula to verify: - \( a_{2985} = 1 + (2985 - 1) imes 4 \).- Calculate: \( 2984 imes 4 = 11,936 \).- Add 1: \( 11,936 + 1 = 11,937 \).Since the calculation is correct, 11,937 is indeed the 2,985th term of the sequence.
Key Concepts
Common Differencen-th Term FormulaSolving EquationsSequence Verification
Common Difference
An arithmetic sequence is defined by its initial term and a constant value known as the common difference. This common difference is crucial because it determines how each subsequent term in the sequence progresses. For the given sequence, the first term is 1 and the common difference is 4.
- Each term is obtained by adding 4 to the previous term.
- This results in the sequence: 1, 5, 9, 13, 17, ..., and so on.
n-th Term Formula
The n-th term formula of an arithmetic sequence allows us to calculate the value of any term based on its position in the sequence. The n-th term formula is given by:
\[ a_n = a_1 + (n-1) \times d \]
\[ a_n = a_1 + (n-1) \times d \]
- \(a_n\) is the n-th term, which you're solving for or verifying.
- \(a_1\) is the first term of the sequence.
- \(n\) is the term number, representing the position of the term in the sequence.
- \(d\) is the common difference, the amount added to each term.
Solving Equations
To determine whether a specific number, like 11,937, is a term in an arithmetic sequence, we employ the n-th term formula to create an equation.
In this situation, we need to figure out if for some positive integer \(n\), the n-th term equals 11,937:
\[ 11,937 = 1 + (n-1) \times 4 \]
Consider the following steps to solve for \(n\):
In this situation, we need to figure out if for some positive integer \(n\), the n-th term equals 11,937:
\[ 11,937 = 1 + (n-1) \times 4 \]
Consider the following steps to solve for \(n\):
- Subtract 1 from both sides to simplify the equation: \(11,936 = (n-1) \times 4\).
- Divide both sides by the common difference 4: \(2,984 = n-1\).
- Solve for \(n\) by adding 1: \(n = 2,985\).
Sequence Verification
Verifying if a specific term belongs to an arithmetic sequence involves re-applying the n-th term formula. It's crucial for ensuring the solution's accuracy. In this instance, after determining \(n = 2,985\), we substitute back into the formula:
\[ a_{2985} = 1 + (2985 - 1) \times 4 \]
\[ a_{2985} = 1 + (2985 - 1) \times 4 \]
- Calculate \(2984 \times 4 = 11,936\).
- Add the initial term \(a_1\): \(11,936 + 1 = 11,937\).
Other exercises in this chapter
Problem 37
Find the first four partial sums and the \(n\)th partial sum of the sequence \(a_{n} .\) \(a_{n}=\sqrt{n}-\sqrt{n+1}\)
View solution Problem 38
The second and the fifth terms of a geometric sequence are 10 and \(1250,\) respectively. Is \(31,250\) a term of this sequence? If so, which term is it?
View solution Problem 38
Find the first four partial sums and the \(n\)th partial sum of the sequence \(a_{n} .\) \(a_{n}=\log \left(\frac{n}{n+1}\right)\) [Hint: Use a property of loga
View solution Problem 39
Find the partial sum \(S_{n}\) of the geometric sequence that satisfies the given conditions. $$ a=5, \quad r=2, \quad n=6 $$
View solution