Problem 38
Question
Write the polynomials in exercises in standard form $$a_{n} x^{n}+a_{n-1} x^{n-1}+\cdots+a_{1} x+a_{0}$$ What are the values of the coefficients \(a_{0}, a_{1}, \ldots, a_{n} ?\) Give the degree of the polynomial. $$ 1+x+\frac{x^{2}}{2}+\frac{x^{3}}{6}+\frac{x^{4}}{24}+\frac{x^{5}}{120} $$
Step-by-Step Solution
Verified Answer
The coefficients of the polynomial are \(a_{0} = 1,\) \(a_{1} = 1,\) \(a_{2} = \frac{1}{2},\) \(a_{3} = \frac{1}{6},\) \(a_{4} = \frac{1}{24},\) and \(a_{5} = \frac{1}{120}.\) The degree of the polynomial is 5.
1Step 1: \(a_{5} = \frac{1}{120},\)
\(a_{4} = \frac{1}{24},\)
2Step 2: \(a_{3} = \frac{1}{6},\)
\(a_{2} = \frac{1}{2},\)
3Step 3: \(a_{1} = 1,\)
\(a_{0} = 1.\)
#Step 2: Find the degree of the polynomial#
Since the highest power of \(x\) present in the polynomial is 5, the degree of the polynomial is 5.
#Final Answer#
Coefficients of the polynomial are:
\(a_{0} = 1,\) \(a_{1} = 1,\) \(a_{2} = \frac{1}{2},\) \(a_{3} = \frac{1}{6},\) \(a_{4} = \frac{1}{24},\) and \(a_{5} = \frac{1}{120}.\) The degree of the polynomial is 5.
Key Concepts
Standard FormCoefficientsDegree of a Polynomial
Standard Form
When working with polynomials, presenting them in **standard form** is crucial. The standard form is a way of organizing a polynomial by descending powers of the variable, which makes it easier to identify key features like coefficients and the degree. Here's the general template for the standard form of a polynomial:
- \( a_{n}x^{n} + a_{n-1}x^{n-1} + \cdots + a_{1}x + a_{0} \)
- \( 1 + x + \frac{x^2}{2} + \frac{x^3}{6} + \frac{x^4}{24} + \frac{x^5}{120} \)
Coefficients
Coefficients are the numerical factors that multiply the terms of a polynomial. Each term in a polynomial comprises a coefficient and a variable part raised to an exponent. Understanding coefficients is essential as they indicate how much each power of the variable contributes to the polynomial.For the given polynomial, the coefficients are:
- \( a_{5} = \frac{1}{120} \) for the term \( \frac{1}{120}x^{5} \)
- \( a_{4} = \frac{1}{24} \) for the term \( \frac{1}{24}x^{4} \)
- \( a_{3} = \frac{1}{6} \) for the term \( \frac{1}{6}x^{3} \)
- \( a_{2} = \frac{1}{2} \) for the term \( \frac{1}{2}x^{2} \)
- \( a_{1} = 1 \) for the term \( 1x \)
- \( a_{0} = 1 \) for the constant term \( 1 \)
Degree of a Polynomial
The degree of a polynomial is determined by the highest power of the variable present in the polynomial. It's a critical attribute because it gives us insight into the polynomial's complexity and behavior at large values of \(x\).In our exercise, the polynomial is:
- \( 1 + x + \frac{x^2}{2} + \frac{x^3}{6} + \frac{x^4}{24} + \frac{x^5}{120} \)
Other exercises in this chapter
Problem 37
Write the polynomials in exercises in standard form $$a_{n} x^{n}+a_{n-1} x^{n-1}+\cdots+a_{1} x+a_{0}$$ What are the values of the coefficients \(a_{0}, a_{1},
View solution Problem 37
Without solving the equation, decide how many solutions it has. $$ \left(x^{4}+2\right)\left(3+x^{2}\right)=0 $$
View solution Problem 38
$$ \begin{aligned} &\text { Find the solutions of }\\\ &\left(x^{2}-a^{2}\right)(x+1)=0, \quad a \text { a constant } \end{aligned} $$
View solution Problem 39
Without expanding, what is the constant term of $$ (x+2)(x+3)(x+4)(x+5)(x+6) ? $$
View solution