Problem 38
Question
The critical temperature of water is higher than that of \(\mathrm{O}_{2}\), because the \(\mathrm{H}_{2} \mathrm{O}\) molecule has (a) fewer electrons than \(\mathrm{O}_{2}\) (b) two covalent bonds (c) V-shape (d) dipole moment
Step-by-Step Solution
Verified Answer
(d) dipole moment
1Step 1: Understanding Critical Temperature
The critical temperature is the temperature above which a substance cannot exist in the liquid state regardless of pressure. It is related to intermolecular forces, as substances with stronger intermolecular forces generally have higher critical temperatures.
2Step 2: Analyzing Water (H2O) vs. Oxygen (O2)
Water (H_{2}O) is a polar molecule with a dipole moment due to its bent V-shape and polar bonds (oxygen being more electronegative than hydrogen). In contrast, O_{2} is a nonpolar molecule as it consists of two identical atoms sharing electrons equally.
3Step 3: Influence of Molecular Properties
The polarity of a molecule affects its intermolecular forces. Water has hydrogen bonding due to its dipole moment, resulting in stronger intermolecular forces compared to the weaker London dispersion forces between nonpolar O_{2} molecules.
4Step 4: Identifying the Correct Reason
The key reason for water's higher critical temperature is its dipole moment, which leads to hydrogen bonding. This is the strongest type of intermolecular force among the given molecules, contributing significantly to water's high critical temperature.
Key Concepts
Understanding Dipole MomentExploring Intermolecular ForcesHydrogen Bonding: A Special Kind of AttractionWhat Makes a Polar Molecule?
Understanding Dipole Moment
The concept of a dipole moment is central to understanding why certain molecules, like water ([0;0;0mH[0;0;0m[0;0;0m_2O[0;0;0m), exhibit higher critical temperatures. A dipole moment occurs in molecules where there is a significant difference in electronegativities between bonded atoms. This difference causes one part of the molecule to be slightly negative and the other to be slightly positive, resulting in a dipole. Water is a perfect example as it has a bent V-shape geometry, which means the dipole moments from its polar O-H bonds do not cancel out. Instead, they add up to create a significant overall dipole moment. This feature is crucial as it contributes to the molecule's ability to engage in strong intermolecular forces.
Exploring Intermolecular Forces
Intermolecular forces are the forces that hold molecules together in a liquid or solid. These forces include
- London dispersion forces
- Dipole-dipole interactions
- Hydrogen bonding
Hydrogen Bonding: A Special Kind of Attraction
Hydrogen bonding is a particularly strong type of dipole-dipole interaction that occurs in molecules where hydrogen is directly bonded to highly electronegative atoms, such as nitrogen, oxygen, or fluorine. In water, each hydrogen atom shares bonds with an oxygen atom, creating partial positive charges on the hydrogens and a partial negative charge on the oxygen. This enables water molecules to form strong hydrogen bonds with each other.
Impact on Physical Properties: Hydrogen bonds significantly influence the physical properties of a substance, including its critical temperature and boiling point.
Examples: Water's high boiling point and critical temperature are key examples of the impact of hydrogen bonding. These bonds must be broken for water to transition from liquid to gas, requiring significant energy.
What Makes a Polar Molecule?
A polar molecule is characterized by an uneven distribution of electron density, resulting in a permanent dipole moment. Water is a classic example of a polar molecule due to its asymmetrical shape and the unequal sharing of electrons between hydrogen and oxygen. The oxygen atom, being more electronegative, pulls the shared electrons closer, resulting in a slight negative charge at one end and a slight positive charge at the other. This polarity is what makes molecules like water highly interactive, influencing their intermolecular forces and, consequently, their physical properties.
Key factors that contribute to molecular polarity include:
Key factors that contribute to molecular polarity include:
- The difference in electronegativity between atoms
- The shape of the molecule
- The resulting dipole moment
Other exercises in this chapter
Problem 36
If two moles of ideal gas at \(540 \mathrm{~K}\) has volume \(44.8 \mathrm{~L}\), then its pressure will be (a) \(1 \mathrm{~atm}\) (b) \(2 \mathrm{~atm}\) (c)
View solution Problem 37
The densities of two gases are in the ratio of \(1: 16\). The ratio of their rates of diffusion is (a) \(16: 1\) (b) \(4: 1\) (c) \(1: 4\) (d) \(1: 16\)
View solution Problem 39
If pressure of 2 mol of an ideal gas at \(546 \mathrm{~K}\) having volume \(44.8\) litre is (a) \(2 \mathrm{~atm}\) (b) \(3 \mathrm{~atm}\) (c) \(4 \mathrm{~atm
View solution Problem 40
\(56 \mathrm{~g}\) of nitrogen and \(96 \mathrm{~g}\) of oxygen are mixed isothermally and at a total pressure of \(10 \mathrm{~atm}\). The partial pressures of
View solution