Problem 37
Question
The densities of two gases are in the ratio of \(1: 16\). The ratio of their rates of diffusion is (a) \(16: 1\) (b) \(4: 1\) (c) \(1: 4\) (d) \(1: 16\)
Step-by-Step Solution
Verified Answer
The ratio of their rates of diffusion is 1:4, matching option (c).
1Step 1: Understanding Graham's Law of Diffusion
Graham's Law states that the rate of diffusion of a gas is inversely proportional to the square root of its density. Mathematically, this is expressed as \( r_1 / r_2 = \sqrt{d_2 / d_1} \), where \( r_1 \) and \( r_2 \) are the rates of diffusion, and \( d_1 \) and \( d_2 \) are their respective densities.
2Step 2: Set the Density Ratio
From the problem, the densities of the two gases are given in the ratio \(1:16\). This means \( d_1 = 1 \) and \( d_2 = 16 \) (taking \( d_1 \) and \( d_2 \) as the relative densities of the two gases).
3Step 3: Calculate the Rate of Diffusion Ratio
Using Graham's Law, substitute the densities into the formula: \( r_1 / r_2 = \sqrt{d_2 / d_1} = \sqrt{16 / 1} = \sqrt{16} = 4 \). Thus, \( r_1 : r_2 = 1:4 \).
4Step 4: Match with Given Options
Compare the calculated ratio \(1:4\) with the given options. It matches option (c) \(1:4\).
Key Concepts
Density of GasesRate of DiffusionInverse Relationship
Density of Gases
Density of gases is a crucial concept that helps us understand how much mass is present in a given volume of a gas. It's often measured as the mass of the gas per unit volume. Typically, when we talk about the density of gases in experiments or problem-solving, we refer to their relative densities. For instance, if we say one gas is denser than the other by a certain factor, it means it contains more mass per volume compared to the other.
The density of a gas can change depending on factors such as pressure and temperature. For example:
The density of a gas can change depending on factors such as pressure and temperature. For example:
- At higher pressures, gas particles are pushed closer together, resulting in higher density.
- At lower temperatures, gas particles move slower and closer together, also increasing density.
- Conversely, higher temperatures will cause gases to expand, reducing density.
Rate of Diffusion
The rate of diffusion refers to how quickly gas particles spread or move from an area of high concentration to an area of low concentration. This can be thought of as how fast two gases mix with each other when they are brought into contact.
Several factors influence the rate of diffusion of gases:
Several factors influence the rate of diffusion of gases:
- The density of the gases, where gases with lower density generally diffuse faster.
- The temperature, as increasing temperature gives gas molecules more kinetic energy, causing them to move and spread more rapidly.
- The molar mass of the gases, with lighter gases moving more swiftly.
Inverse Relationship
An inverse relationship in mathematics and science describes a situation where one variable increases while the other decreases. In the context of Graham's Law of Diffusion, this refers to the relationship between the rate of diffusion of gases and their densities.
In Graham's Law, this inverse relationship is captured by the equation:\[\frac{r_1}{r_2} = \sqrt{\frac{d_2}{d_1}}\]Where \(r_1\) and \(r_2\) represent the rates of diffusion, and \(d_1\) and \(d_2\) are the constants representing the densities of the two gases. As you can see, if one gas is denser \(d_2 > d_1\), its rate of diffusion \(r_2\) will be slower compared to a less dense gas \(r_1\).
Grasping this relationship is essential to understand how gases behave in various environments and why certain gases spread faster than others. For instance, lighter gases like helium rapidly escape from balloons because they diffuse faster than heavier gases. Understanding this inverse relationship allows us to predict and control the behavior of gases in various scientific and industrial applications.
In Graham's Law, this inverse relationship is captured by the equation:\[\frac{r_1}{r_2} = \sqrt{\frac{d_2}{d_1}}\]Where \(r_1\) and \(r_2\) represent the rates of diffusion, and \(d_1\) and \(d_2\) are the constants representing the densities of the two gases. As you can see, if one gas is denser \(d_2 > d_1\), its rate of diffusion \(r_2\) will be slower compared to a less dense gas \(r_1\).
Grasping this relationship is essential to understand how gases behave in various environments and why certain gases spread faster than others. For instance, lighter gases like helium rapidly escape from balloons because they diffuse faster than heavier gases. Understanding this inverse relationship allows us to predict and control the behavior of gases in various scientific and industrial applications.
Other exercises in this chapter
Problem 35
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If two moles of ideal gas at \(540 \mathrm{~K}\) has volume \(44.8 \mathrm{~L}\), then its pressure will be (a) \(1 \mathrm{~atm}\) (b) \(2 \mathrm{~atm}\) (c)
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