Problem 37
Question
If \(f(x)=x^{3}+c x^{2}+4 x-1\) for some constant \(c\) and \(f(1)=2,\) find \(c .[\text {Hint: Use the rule of } f \text { to compute } f(1) .]\)
Step-by-Step Solution
Verified Answer
Answer: -2
1Step 1: Substitute the given value x = 1 into the function f(x)
Substitute \(x = 1\) into the function \(f(x)=x^3 + cx^2 + 4x - 1\) to get:
$$
f(1) = (1)^3 + c(1)^2 + 4(1) -1
$$
2Step 2: Simplify the expression
Now, we simplify the expression obtained in step 1:
$$
f(1) = 1 + c + 4 - 1
$$
$$
f(1) = c + 4
$$
3Step 3: Use the given value for f(1) and solve for c
We know that \(f(1) = 2\). Now, we can replace f(1) with 2, and solve for c:
$$
2 = c + 4
$$
Rearrange to solve for c:
$$
c = 2 - 4
$$
Finally, compute the value for c:
$$
c = -2
$$
Thus, the constant \(c\) for the function is -2.
Key Concepts
Function EvaluationEquation SolvingConstant Determination
Function Evaluation
Function evaluation is an important process in which we substitute specific values into a given function to find corresponding outputs. In this exercise, we are asked to evaluate the polynomial function defined as \( f(x) = x^3 + cx^2 + 4x - 1 \) at a specific point, which is \( x = 1 \). By substituting \( x = 1 \) into the function, we calculate \( f(1) \), moving through each term:
- The first term, \( x^3 \), becomes \( 1^3 = 1 \).
- The second term, \( cx^2 \), is \( c \times 1^2 = c \).
- The third term, \( 4x \), becomes \( 4 \times 1 = 4 \).
- The constant in the equation remains \(-1\).
Equation Solving
To solve an equation, you must isolate the unknown variable. In this context, after evaluating the function at \( x = 1 \), we received an expression \( f(1) = c + 4 \). We know that the function value \( f(1) \) is given as \( 2 \). By setting \( c + 4 = 2 \), we form a simple linear equation. To find \( c \), perform the following steps:
- First, subtract 4 from both sides of the equation to isolate \( c \). This gives us \( c = 2 - 4 \).
- Proceed to simplify the result to find \( c = -2 \).
Constant Determination
Determining a constant in a function often involves plugging in known values and solving for the unknown. The constant \( c \) in our exercise must satisfy the condition \( f(1) = 2 \). Through function evaluation and solving the subsequent equation \( c + 4 = 2 \), we discern that \( c \) must be \(-2\). This step is crucial for several reasons:
- Firstly, it allows the function to pass through given points, maintaining the desired properties of the function.
- Secondly, constants greatly affect the shape and position of polynomial functions when plotted.
Other exercises in this chapter
Problem 37
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