Problem 37
Question
Find an equation of the line that satisfies the given conditions. Through \((1,7) ;\) parallel to the line passing through \((2,5)\) and \((-2,1)\)
Step-by-Step Solution
Verified Answer
The equation of the line is \(y = x + 6\).
1Step 1: Find the Slope of the Given Line
First, we need to find the slope of the line passing through points \((2, 5)\) and \((-2, 1)\). Use the slope formula: \[m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 5}{-2 - 2} = \frac{-4}{-4} = 1\]Thus, the slope of the line is \(m = 1\).
2Step 2: Use the Slope for the Parallel Line
Since lines that are parallel have the same slope, the slope of the line we are looking for is also \(m = 1\).
3Step 3: Use the Point-Slope Form of a Line
Now, we have a point \((1, 7)\) through which the line passes and the slope \(m = 1\). Use the point-slope form of a line equation: \[y - y_1 = m(x - x_1)\]Substitute \(x_1 = 1\), \(y_1 = 7\), and \(m = 1\):\[y - 7 = 1(x - 1)\]
4Step 4: Simplify the Equation
Simplify the equation \[y - 7 = x - 1\]to the slope-intercept form:\[y = x + 6\].This is the equation of the line parallel to the given one passing through point \((1, 7)\).
Key Concepts
Understanding the SlopeExploring the Point-Slope FormConcept of Parallel Lines
Understanding the Slope
In the world of geometry, the slope of a line is a crucial concept. Imagine you are on a hill, standing at one point and looking towards another. That's essentially what slope is – it's the measure of the steepness or inclination of a line. Mathematically, it's represented as the ratio of the change in the vertical direction (between two points on the line) to the change in the horizontal direction. This is often denoted by the symbol \( m \).
For any two given points on a straight line – say \( (x_1, y_1) \) and \( (x_2, y_2) \) – you can calculate the slope \( m \) using the formula:
For any two given points on a straight line – say \( (x_1, y_1) \) and \( (x_2, y_2) \) – you can calculate the slope \( m \) using the formula:
- \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
Exploring the Point-Slope Form
When you're given a point and a slope, and you need to find the equation of a line, the point-slope form is your best friend. It offers a straightforward way to frame the linear equation by directly utilizing the slope and any specific point that the line passes through. The general structure for the point-slope form is:
This versatility makes the point-slope form a foundational tool in algebra.
- \( y - y_1 = m(x - x_1) \)
- \( (x_1, y_1) \) is a point on the line
- \( m \) is the slope of the line
This versatility makes the point-slope form a foundational tool in algebra.
Concept of Parallel Lines
Imagine two train tracks running side by side forever. That's how parallel lines behave geometrically – they never intersect and always maintain a constant distance between each other.
In terms of linear equations, when two lines are parallel, they share an identical slope. This is because they have the same pitch or direction but start at different points. Hence, their slopes, represented by \( m \), are equal.
For example, if you know a line with equation \( y = mx + b \) and you want to find a line parallel to it, that new line will also have a slope \( m \). The only difference will be in the y-intercept, which determines where the line crosses the y-axis. This constant slope property is what ensures the lines never meet or diverge from one another. Understanding this concept is key when solving problems involving parallel lines.
In terms of linear equations, when two lines are parallel, they share an identical slope. This is because they have the same pitch or direction but start at different points. Hence, their slopes, represented by \( m \), are equal.
For example, if you know a line with equation \( y = mx + b \) and you want to find a line parallel to it, that new line will also have a slope \( m \). The only difference will be in the y-intercept, which determines where the line crosses the y-axis. This constant slope property is what ensures the lines never meet or diverge from one another. Understanding this concept is key when solving problems involving parallel lines.
Other exercises in this chapter
Problem 36
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