Problem 36
Question
\(11-36\) Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts. $$ y=16-x^{4} $$
Step-by-Step Solution
Verified Answer
\(x\)-intercepts: \((-2, 0)\) and \((2, 0)\); \(y\)-intercept: \((0, 16)\).
1Step 1: Create a Table of Values
To construct a table of values for the equation \(y = 16 - x^4\), choose a range of \(x\) values to calculate corresponding \(y\) values. 1. Let \(x = -2\): \(y = 16 - (-2)^4 = 16 - 16 = 0\)2. Let \(x = -1\): \(y = 16 - (-1)^4 = 16 - 1 = 15\)3. Let \(x = 0\): \(y = 16 - 0^4 = 16\)4. Let \(x = 1\): \(y = 16 - 1^4 = 15\)5. Let \(x = 2\): \(y = 16 - 2^4 = 0\)6. Let \(x = 3\): \(y = 16 - 3^4 = -65\)(point goes off visible graph, included to indicate shape). This gives the table of values: \[\begin{array}{c|c}x & y \\hline-2 & 0 \-1 & 15 \0 & 16 \1 & 15 \2 & 0 \3 & -65 \\end{array}\]
2Step 2: Plot the Points and Sketch the Graph
Using the table of values from Step 1, plot the points on a coordinate system: \((-2, 0), (-1, 15), (0, 16), (1, 15), (2, 0), (3, -65)\). The points \((-2, 0)\) and \((2, 0)\) show the \(x\)-intercepts, and the graph is symmetric with respect to the \(y\)-axis. The plotted points will outline a curve opening downwards. Draw this graph smoothly passing through the plotted points.
3Step 3: Determine the x-intercepts
The \(x\)-intercepts are the points where the graph crosses the \(x\)-axis. These occur where \(y = 0\).From the table, see that the \(x\)-intercepts occur at \(x = -2\) and \(x = 2\). Thus, the \(x\)-intercepts are \((-2, 0)\) and \((2, 0)\).
4Step 4: Determine the y-intercept
The \(y\)-intercept is the point where the graph crosses the \(y\)-axis. This occurs where \(x = 0\).From the table, when \(x = 0\), \(y = 16\). Thus, the \(y\)-intercept is \((0, 16)\).
Key Concepts
Polynomial FunctionsX-interceptsY-interceptsCoordinate SystemTable of Values
Polynomial Functions
Polynomial functions are expressions involving variables raised to powers, combined using addition, subtraction, and multiplication. The general form of a polynomial function is:
- \(a_nx^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0\)
- \(a_n, a_{n-1}, \ldots, a_0\) are constants
- \(x\) represents the variable
- \(n\) is a non-negative integer, determining the degree of the polynomial
X-intercepts
X-intercepts are the points where a graph crosses the x-axis. These points occur where the output of the function \(y\) is zero. For our example, \(y = 16 - x^4\), the x-intercepts are places where the equation equals zero. To find these:
- Set \(y = 0\).
- Resulting in \(16 - x^4 = 0\).
- Solving gives \(x^4 = 16\), which results in \(x = \pm2\).
Y-intercepts
Y-intercepts occur where a graph crosses the y-axis. For this to happen, the value of \(x\) is 0. So in our function \(y = 16 - x^4\), simply substitute \(x = 0\) into the expression.The equation becomes:
- \(y = 16 - 0^4\)
- This simplifies to \(y = 16\).
Coordinate System
A coordinate system, like the Cartesian plane, serves to visually plot mathematical functions. It consists of two perpendicular axes, the x-axis and y-axis. Each point on this plane is defined by a pair of numerical coordinates \((x, y)\).In the context of our example \(y = 16 - x^4\), these coordinates allow us to precisely mark points derived from the table of values. This helps create a visual representation of the data and the possible curve of the polynomial function.
- The x-coordinate represents horizontal placement.
- The y-coordinate provides vertical positioning.
Table of Values
Creating a table of values is a methodical way of understanding functions. It involves selecting various x-values, plugging each into your polynomial equation, and solving for the corresponding y-values. For \(y = 16 - x^4\), we calculated some values:
- \(x = -2\), then \(y = 0\)
- \(x = -1\), then \(y = 15\)
- \(x = 0\), then \(y = 16\)
- \(x = 1\), then \(y = 15\)
- \(x = 2\), then \(y = 0\)
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