Problem 37
Question
An online grocery store charges for delivery based on the equation \(C=0.30 p\), where \(C\) represents the cost in dollars, and \(p\) represents the weight of the groceries in pounds. Label the horizontal axis \(p\) and the vertical axis \(C\), and graph the equation \(C=0.30 p\) for nonnegative values of \(p\).
Step-by-Step Solution
Verified Answer
Graph a straight line from (0,0) through points like (5,1.5) and label axes.
1Step 1: Identify Variables and Constants
In the equation \(C = 0.30 p\), \(C\) is the delivery cost in dollars, and \(p\) is the weight in pounds. The number 0.30 is the fixed rate per pound.
2Step 2: Set Up the Coordinate Axes
The horizontal axis (x-axis) is labeled as \(p\) and represents the weight of the groceries in pounds. The vertical axis (y-axis) is labeled as \(C\) and represents the cost in dollars.
3Step 3: Determine Graph Range
Since we are asked to graph for nonnegative values, consider \(p \geq 0\). Therefore, the graph should start from the origin (0,0) and extend to positive values on both axes.
4Step 4: Find and Plot Key Points
Choose a few values of \(p\) to calculate \(C\), e.g., \(p = 0, 5, 10\). Calculate the corresponding \(C\) values: \(C(0) = 0.30 \times 0 = 0\), \(C(5) = 0.30 \times 5 = 1.5\), \(C(10) = 0.30 \times 10 = 3\). Plot the points: (0,0), (5,1.5), and (10,3) on the graph.
5Step 5: Draw the Graph Line
Connect the plotted points with a straight line. Since the equation \(C = 0.30 p\) is linear, the graph is a straight line passing through the origin with a slope of 0.30.
6Step 6: Label the Graph
Ensure the axes have labels: \(p\) for the horizontal axis and \(C\) for the vertical axis. Mark the scale on both axes for clarity, showing values at consistent intervals.
Key Concepts
Coordinate AxesSlopeLinear FunctionGraph Plotting
Coordinate Axes
In graphing linear equations, understanding the coordinate axes is crucial. The coordinate system is composed of two perpendicular lines: the horizontal line and the vertical line.
- The horizontal line is known as the x-axis.
- The vertical line is referred to as the y-axis.
Slope
The slope of a line is a measure that explains the steepness or incline of the line. It indicates how much the dependent variable (cost, in our case) will change for a change in the independent variable (weight in our case).
and helps in predicting how changes in one variable affect the other.
- In the equation \(C = 0.30 p\), the slope is 0.30.
- This number represents the cost increase per pound of grocery weight.
and helps in predicting how changes in one variable affect the other.
Linear Function
A linear function, like the one given by \(C = 0.30 p\), is an algebraic equation where each term is either a constant or the product of a constant and a single variable. This type of function forms a straight line when graphed.
- The general form of a linear function is \(y = mx + b\), where \(m\) is the slope, and \(b\) is the y-intercept.
- Our equation's format lacks the \(b\) term, making it a line through the origin.
Graph Plotting
Plotting a graph begins by identifying the points that fit the equation. Choose values for the independent variable \(p\), calculate the dependent variable \(C\), and then plot these coordinates on the graph.
This line not only visualizes our linear function but also represents the relationship between weight and cost as described by our equation, concluding with labeling the axes and marking units for clarity. This systematic approach ensures accurate representation
of the data and function being analyzed.
- For \(p = 0\), \(C = 0\).
- For \(p = 5\), \(C = 1.5\).
- For \(p = 10\), \(C = 3\).
This line not only visualizes our linear function but also represents the relationship between weight and cost as described by our equation, concluding with labeling the axes and marking units for clarity. This systematic approach ensures accurate representation
of the data and function being analyzed.
Other exercises in this chapter
Problem 35
Contains the point \((1,3)\) and is parallel to the line \(x+\) \(5 y=9\)
View solution Problem 35
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View solution Problem 39
Contains the point \((-1,3)\) and is perpendicular to the line \(2 x-y=4\)
View solution