Problem 36
Question
Prove that $$\lim _{x \rightarrow 2} \frac{1}{x}=\frac{1}{2}$$
Step-by-Step Solution
Verified Answer
Yes, the limit \( \lim_{x \to 2} \frac{1}{x} = \frac{1}{2} \) is proven by the epsilon-delta definition.
1Step 1: Understand the limit definition
The expression \( \lim_{x \to a} f(x) = L \) means that as \( x \) approaches \( a \), the function \( f(x) \) approaches the limit \( L \). In this exercise, as \( x \) approaches \( 2 \), \( \frac{1}{x} \) approaches \( \frac{1}{2} \).
2Step 2: Define the epsilon-delta criterion
According to the epsilon-delta definition of a limit, we say \( \lim_{x \to 2} \frac{1}{x} = \frac{1}{2} \) if for every \( \varepsilon > 0 \), there exists a \( \delta > 0 \) such that if \( 0 < |x - 2| < \delta \), then \( \left| \frac{1}{x} - \frac{1}{2} \right| < \varepsilon \).
3Step 3: Find an expression for \( \left| \frac{1}{x} - \frac{1}{2} \right| \)
Start by simplifying the expression \( \left| \frac{1}{x} - \frac{1}{2} \right| \). You can rewrite it as:\[ \left| \frac{1}{x} - \frac{1}{2} \right| = \left| \frac{2 - x}{2x} \right|. \]
4Step 4: Ensure bounding of the expression
We need to bound \( \left| \frac{2-x}{2x} \right| \) such that it is less than \( \varepsilon \). Assume \( |x - 2| < \delta \). This means \( 1.9 < x < 2.1 \), ensuring \( x \) is close to 2 but not equal to zero.
5Step 5: Choose \( \delta \) based on \( \varepsilon \)
To ensure \( \left| \frac{2-x}{2x} \right| < \varepsilon \), select \( \delta \leq 0.1 \) so that \( 2x \approx 4 \) when \( x \approx 2 \). Therefore, choose \( \delta = \min \left( 0.1, \frac{2\varepsilon}{5} \right) \).
6Step 6: Validate the epsilon-delta inequality
Substitute \( \delta \) into the expressions, giving: \[ \left| \frac{2-x}{2x} \right| < \left| \frac{2-x}{4} \right| < \varepsilon.\] This inequality ensures the limit is satisfied, proving that for every \( \varepsilon > 0 \), a corresponding \( \delta \) can be selected.
Key Concepts
Limit ProofEpsilon-Delta CriterionLimit of a Function
Limit Proof
The idea of a limit proof is to demonstrate, through logical reasoning, that a function approaches a certain value as the input nears a specified point. These proofs help us rigorously verify results that might seem obvious intuitively. In this problem, the limit we need to prove is:
- \( \lim_{x \to 2} \frac{1}{x} = \frac{1}{2} \)
- Clarify the goal using the limit definition.
- Apply the epsilon-delta criteria to establish bounds.
- Pick appropriate values for delta based on epsilon to satisfy the inequality.
Epsilon-Delta Criterion
The epsilon-delta criterion is a formal way to define the limit of a function. Here, the primary concept revolves around two very small positive numbers called epsilon (\( \varepsilon \)) and delta (\( \delta \)).
Our specific task is to ensure:
- Epsilon (\( \varepsilon \)) represents the maximum allowable difference between the function's value and the limit.
- Delta (\( \delta \)) relates to how tightly the input values must cluster around the point of approach to maintain that difference lower than epsilon.
Our specific task is to ensure:
- If \( 0 < |x - 2| < \delta \), then \( \left| \frac{1}{x} - \frac{1}{2} \right| < \varepsilon \)
Limit of a Function
A limit describes the behavior of a function as its input approaches a certain value. It doesn't necessarily have to be the function's value at that point, but rather the value the function tends towards.
Limits are foundational in calculus, embodying the idea of approaching a point continuously. Understanding limits sequentially helps grasp the concept better.
Limits are foundational in calculus, embodying the idea of approaching a point continuously. Understanding limits sequentially helps grasp the concept better.
- First, think about the function's behavior, like \( \frac{1}{x} \) when \( x \) is near but not equal to 2.
- Consider what happens to \( \frac{1}{x} \) as \( x \) grows exceedingly close to 2. The closer \( x \) is to 2, \( \frac{1}{x} \) approaches 0.5.
Other exercises in this chapter
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