Problem 36
Question
If \(2 x \leqslant g(x) \leqslant x^{4}-x^{2}+2\) for all \(x,\) evaluate \(\lim _{x \rightarrow 1} g(x)\)
Step-by-Step Solution
Verified Answer
The limit of \(g(x)\) as \(x\) approaches 1 is 2.
1Step 1: Express the Inequality Constraints
The problem states that for all \(x\), \(2x \leq g(x) \leq x^4 - x^2 + 2\). We want to evaluate the limit of \(g(x)\) as \(x\) approaches \(1\).
2Step 2: Apply the Limit to Each Part of the Inequality
To find \(\lim_{{x \to 1}} g(x)\), we consider the limits of the boundary functions: \(2x\) and \(x^4 - x^2 + 2\) as \(x\) approaches \(1\).
3Step 3: Calculate the Left Boundary Limit
Calculate \(\lim_{{x \to 1}} 2x\): Since \(2x\) is continuous, \(\lim_{{x \to 1}} 2x = 2 \cdot 1 = 2\).
4Step 4: Calculate the Right Boundary Limit
For the right boundary, compute \(\lim_{{x \to 1}} (x^4 - x^2 + 2)\). Substituting \(x = 1\), we get \(1^4 - 1^2 + 2 = 2\).
5Step 5: Apply the Squeeze Theorem
Since \(2x \leq g(x) \leq x^4 - x^2 + 2\) for all \(x\), and both bounds approach 2 as \(x\) approaches 1, by the Squeeze Theorem, \(\lim_{{x \to 1}} g(x) = 2\).
Key Concepts
Squeeze TheoremInequalities in CalculusContinuity of Functions
Squeeze Theorem
The Squeeze Theorem is a valuable tool in calculus for finding the limit of a function when it is difficult to compute directly. It is particularly useful when a function is "trapped" between two other functions whose limits are known or easier to determine.
The theorem works by "squeezing" the function of interest between two simpler functions. If the upper and lower functions converge to the same limit at a certain point, then the function squeezed between them must also converge to that same limit.
The theorem works by "squeezing" the function of interest between two simpler functions. If the upper and lower functions converge to the same limit at a certain point, then the function squeezed between them must also converge to that same limit.
- First, you identify two functions, say \( f(x) \) and \( h(x) \), such that \( f(x) \leq g(x) \leq h(x) \) over an interval.
- Next, compute \( \lim_{{x \to a}} f(x) \) and \( \lim_{{x \to a}} h(x) \).
- If both limits are equal to a number \( L \), then \( \lim_{{x \to a}} g(x) = L \).
Inequalities in Calculus
Understanding and working with inequalities is essential in calculus. Inequalities allow us to estimate and bound the behavior of functions, providing crucial insights into their properties.
In the context of limits, inequalities can help us establish upper and lower bounds for functions. This is especially useful when applying the Squeeze Theorem or similar techniques.
In the context of limits, inequalities can help us establish upper and lower bounds for functions. This is especially useful when applying the Squeeze Theorem or similar techniques.
- Inequalities can inform us about the continuity and boundedness of a function.
- We often express functions in terms of inequalities to simplify the evaluation of a limit.
- Understanding the interplay between functions using inequalities helps in establishing crucial relationships, such as dominance or convergence, as \( x \) approaches a particular value.
Continuity of Functions
Continuity is a fundamental property in calculus that implies a function behaves predictably and smoothly without any jumps or interruptions.
A function is continuous at a point \( x = a \) if three conditions are satisfied:
Additionally, continuous functions are more predictable, which aids in applying theorems like the Intermediate Value Theorem, further emphasizing the importance of continuity in mathematical analysis and problem-solving.
A function is continuous at a point \( x = a \) if three conditions are satisfied:
- The function \( f(x) \) is defined at \( a \).
- The limit \( \lim_{{x \to a}} f(x) \) exists.
- The limit and the function value are equal, i.e., \( \lim_{{x \to a}} f(x) = f(a) \).
Additionally, continuous functions are more predictable, which aids in applying theorems like the Intermediate Value Theorem, further emphasizing the importance of continuity in mathematical analysis and problem-solving.
Other exercises in this chapter
Problem 36
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