Problem 36
Question
Graph each inequality in two variables. $$ 3 x-y \leq 4 $$
Step-by-Step Solution
Verified Answer
Shade above the solid line of \(y = 3x - 4\).
1Step 1: Write the Inequality in Slope-Intercept Form
Start with the inequality \(3x - y \leq 4\). To write it in slope-intercept form \(y = mx + b \), solve for \(y\). Add \(y\) to both sides to get \(3x \leq y + 4\). Subtract \(4\) from both sides: \(3x - 4 \leq y\). Finally, rewrite it as \(y \geq 3x - 4\).
2Step 2: Identify the Line for the Boundary
The boundary line is \(y = 3x - 4\), which you'll graph using a dashed or solid line. In this case, use a solid line because the inequality is \(\leq\), indicating that points on the line are included in the solution.
3Step 3: Graph the Boundary Line
To graph the line, identify the y-intercept, which is -4. Start by plotting the y-intercept (0, -4) on the graph. Then use the slope, which is 3 (or \(\frac{3}{1}\)), to find another point: from (0, -4), go up 3 units and right 1 unit to arrive at (1, -1). Connect these points with a solid line.
4Step 4: Shade the Solution Region
Since the inequality is \(y \geq 3x - 4\), shade the region above the line. This represents all points \((x, y)\) that make the inequality true.
Key Concepts
Slope-Intercept FormBoundary LineSolution RegionInequalities in Two Variables
Slope-Intercept Form
The slope-intercept form of a line is a popular way to express the equation of a line, especially useful for graphing. The formula is expressed as \( y = mx + b \). Here, \( m \) represents the slope of the line, telling you how steep the line is. The \( b \) in the formula is the y-intercept, the point where the line crosses the y-axis.
Writing the inequality \(3x - y \leq 4\) in slope-intercept form helps simplify graphing. First, we solve for \( y \). Add \( y \) to both sides:
Writing the inequality \(3x - y \leq 4\) in slope-intercept form helps simplify graphing. First, we solve for \( y \). Add \( y \) to both sides:
- \(3x \leq y + 4\)
- \( y \geq 3x - 4 \)
Boundary Line
In inequalities, the boundary line is straight from the slope-intercept form of the inequality. It acts as a delimiter for the solution region on the graph. For our inequality \( y \geq 3x - 4 \), the boundary line is \( y = 3x - 4 \), represented as a line on the graph.
- If the inequality sign is \( \leq \) or \( \geq \), the line is solid, indicating points on the line are part of the solution set.
- If the inequality were \( > \) or \( < \), you'd use a dashed line to show points on the line aren't included.
Solution Region
The solution region refers to the part of the graph that contains all possible solutions (\( x, y \) pairs) that satisfy the inequality. Once you graph the boundary line, you need to determine which side of the line contains the solutions.
Since our inequality after rearranging is \( y \geq 3x - 4 \), the solution region is above the boundary line. This means any point in the shaded area will satisfy the inequality. Remember:
Since our inequality after rearranging is \( y \geq 3x - 4 \), the solution region is above the boundary line. This means any point in the shaded area will satisfy the inequality. Remember:
- Shade above the line when the inequality is \( \geq \).
- Shade below the line for \( \leq \).
Inequalities in Two Variables
An inequality in two variables, such as \(3x - y \leq 4\), can be graphically represented to better visualize the solutions. It involves finding a range of \( x \) and \( y \) values that make the inequality true, unlike equations which provide precise solutions.
The process begins by rearranging the inequality to the slope-intercept form. This helps plot the boundary line. The inequality symbol dictates whether the boundary line is solid or dashed and where the solution region is. Finally, shading the correct side of the boundary line illustrates all valid \((x, y)\) points.
The process begins by rearranging the inequality to the slope-intercept form. This helps plot the boundary line. The inequality symbol dictates whether the boundary line is solid or dashed and where the solution region is. Finally, shading the correct side of the boundary line illustrates all valid \((x, y)\) points.
- Use slope-intercept form \( y = mx + b \) to handle inequalities in two variables easily.
- Graphing makes complex solutions manageable and visually comprehensible.
Other exercises in this chapter
Problem 36
Hint: For Exercises 33 through 38 , first divide the equation through by the coefficient of \(x^{2}\) (or \(\left.y^{2}\right)\). $$ 7(x-1)^{2}+7(y-3)^{2}=63 $$
View solution Problem 36
Graph each system. $$ \left\\{\begin{array}{l} x^{2}-y^{2} \geq 1 \\ \frac{x^{2}}{16}+\frac{y^{2}}{4} \leq 1 \\ y \geq 1 \end{array}\right. $$
View solution Problem 37
Identify whether each equation, when graphed, will be a parabola, circle,ellipse, or hyperbola. Sketch the graph of each equation. If a parabola, label the vert
View solution Problem 37
Hint: For Exercises 33 through 38 , first divide the equation through by the coefficient of \(x^{2}\) (or \(\left.y^{2}\right)\). $$ 4(x+1)^{2}+4(y-3)^{2}=12 $$
View solution