Problem 35
Question
Exer. 35-38: Find the values of \(x\) and \(y\), where \(x\) and \(y\) are real numbers. $$ 4+(x+2 y) i=x+2 i $$
Step-by-Step Solution
Verified Answer
\( x = 4 \), \( y = -1 \)
1Step 1: Separate Real and Imaginary Parts
Given the equation \( 4 + (x + 2y)i = x + 2i \), we begin by grouping the real parts and the imaginary parts on both sides of the equation. This gives us the system: Real part: \( 4 = x \) Imaginary part: \( x + 2y = 2 \).
2Step 2: Solve for x
From the real part equation, \( 4 = x \), we can immediately find that \( x = 4 \).
3Step 3: Substitute x into Imaginary Part Equation
Now that we have found \( x = 4 \), substitute this value into the equation from the imaginary part: \( 4 + 2y = 2 \).
4Step 4: Solve for y
With the equation \( 4 + 2y = 2 \), solve for \( y \): Subtract 4 from both sides to get \( 2y = -2 \). Divide both sides by 2 to isolate \( y \): \( y = -1 \).
Key Concepts
Understanding Real NumbersExploring Imaginary NumbersSolving Algebraic Equations
Understanding Real Numbers
Real numbers encompass all the numbers we typically use in everyday arithmetic. These include both positive and negative numbers, as well as zero. Real numbers can be whole numbers, also known as integers, or they can be fractions or decimals, also termed rational numbers. Let’s break it down further:
- Integers: Whole numbers that can be positive, negative, or zero (e.g., -3, 0, 4).
- Rational Numbers: Numbers that can be expressed as a fraction of two integers, like 1/2 or 0.75.
- Irrational Numbers: These numbers cannot be written as a simple fraction, such as the square root of 2 or π.
Exploring Imaginary Numbers
Imaginary numbers are a fascinating extension of the number system. They introduce the concept of the square root of negative numbers, which real numbers cannot address. The basic unit of imaginary numbers is \(i\), defined by the property \(i^2 = -1\). Here are some key points about imaginary numbers:
- They help solve equations that don't have real solutions, such as \(x^2 + 1 = 0\).
- Imaginary numbers combined with real numbers form complex numbers, expressed as \(a + bi\), where \(a\) and \(b\) are real numbers.
- In the equation from the exercise, \(i\) helps separate the real and imaginary components, simplifying the process of solving for \(x\) and \(y\).
Solving Algebraic Equations
Algebraic equations are integral to mathematics, serving as the basis for solving problems that entail finding unknown values. These equations can take various forms, such as linear, quadratic, or polynomial, and the techniques to solve them will depend on the equation's complexity. Let's breakdown the essentials of solving algebraic equations:
- Identify the type of equation based on its structure.
- Use algebraic methods, such as substitution or elimination, to isolate variables.
- Apply arithmetic operations carefully to simplify equations.
Other exercises in this chapter
Problem 35
Exer. 21-70: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ 0 \leq 4-\frac{1}{3} x
View solution Problem 35
Exer. 1-50: Solve the equation. $$ x^{4}-25 x^{2}+144=0 $$
View solution Problem 35
Exer. \(31-44\) : Solve by using the quadratic formula. $$ 2 x^{2}-3 x-4=0 $$
View solution Problem 36
In electrical theory, Ohm's law states that \(I=V / R\), where \(I\) is the current in amperes, \(V\) is the electromotive force in volts, and \(R\) is the resi
View solution