Problem 35
Question
Exer. 21-70: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ 0 \leq 4-\frac{1}{3} x<2 $$
Step-by-Step Solution
Verified Answer
\((6, 12]\)
1Step 1: Analyze the Double Inequality
The given inequality is a compound inequality: \( 0 \leq 4 - \frac{1}{3}x < 2 \). It means that \( 4 - \frac{1}{3}x \) is greater than or equal to 0 and less than 2. We will break it into two separate inequalities and solve each one independently.
2Step 2: Solve the Left Inequality
The left inequality from the compound inequality is \( 0 \leq 4 - \frac{1}{3}x \). Subtract 4 from both sides: \( -4 \leq -\frac{1}{3}x \). Then, multiply both sides by -3 (remember to flip the inequality sign, since we are multiplying by a negative number): \( 12 \geq x \). This simplifies to \( x \leq 12 \).
3Step 3: Solve the Right Inequality
The right inequality from the compound inequality is \( 4 - \frac{1}{3}x < 2 \). Subtract 4 from both sides: \( -\frac{1}{3}x < -2 \). Then, multiply both sides by -3 (again flipping the inequality sign): \( x > 6 \).
4Step 4: Combine the Solutions
To satisfy both inequalities, \( x \) must be greater than 6 and less than or equal to 12. Combining these inequalities, we get \( 6 < x \leq 12 \). This can be expressed in interval notation as \((6, 12]\).
Key Concepts
Compound InequalitiesInterval NotationMathematical Problem Solving
Compound Inequalities
Compound inequalities involve combining two or more inequalities that must be true at the same time. In the exercise, the compound inequality is given as:
Remember, when solving these inequalities, the rules applied to both inequalities are the same, but each must be handled separately to ensure accuracy when combining them later.
- \(0 \leq 4 - \frac{1}{3}x < 2\)
- \(x\) must make \(4 - \frac{1}{3}x\) greater than or equal to 0.
- \(x\) must make \(4 - \frac{1}{3}x\) less than 2.
Remember, when solving these inequalities, the rules applied to both inequalities are the same, but each must be handled separately to ensure accuracy when combining them later.
Interval Notation
Interval notation is a mathematical shorthand used to express a set of numbers along a continuous range. It is especially handy when discussing solutions to inequalities. In our solution, the interval notation \((6, 12]\) is used.
Here's a quick breakdown of the symbols:
Interval notation succinctly represents the solution space and is particularly useful for communicating the range over which an inequality holds true.
Here's a quick breakdown of the symbols:
- Parentheses \((\) or \()\) indicate that an endpoint is not included. For example, \(x > 6\) is expressed as \((6, \infty)\).
- Brackets \([\) or \(]\) show that an endpoint is included. For example, \(x \leq 12\) is expressed as \((-\infty, 12]\).
Interval notation succinctly represents the solution space and is particularly useful for communicating the range over which an inequality holds true.
Mathematical Problem Solving
Solving mathematical problems, such as inequalities, often involves breaking down complex instructions into manageable steps. This approach improves understanding and ensures accuracy.
- First, carefully read and comprehend the problem statement, as seen with the given compound inequality: \(0 \leq 4 - \frac{1}{3}x < 2\).
- Break it into smaller, easier-to-solve parts. Tackle the left and right inequalities separately: find solutions for \(0 \leq 4 - \frac{1}{3}x\) and \(4 - \frac{1}{3}x < 2\).
- Solve each part using standard algebraic methods like addition, subtraction, multiplication, or division. Be aware of rules: multiplying or dividing by a negative number reverses the inequality sign.
- Combine your results logically, ensuring all conditions are satisfied simultaneously. Check results for accuracy.
Other exercises in this chapter
Problem 35
Solve the equation. $$\frac{9 x}{3 x-1}=2+\frac{3}{3 x-1}$$
View solution Problem 35
Exer. 1-40: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ \frac{4}{3 x-2} \leq \frac{2}{x+1} $$
View solution Problem 35
Exer. 1-50: Solve the equation. $$ x^{4}-25 x^{2}+144=0 $$
View solution Problem 35
Exer. 35-38: Find the values of \(x\) and \(y\), where \(x\) and \(y\) are real numbers. $$ 4+(x+2 y) i=x+2 i $$
View solution