Problem 34
Question
Write the polynomials in exercises in standard form $$a_{n} x^{n}+a_{n-1} x^{n-1}+\cdots+a_{1} x+a_{0}$$ What are the values of the coefficients \(a_{0}, a_{1}, \ldots, a_{n} ?\) Give the degree of the polynomial. $$ 3-2(x-5)^{2} $$
Step-by-Step Solution
Verified Answer
Answer: The coefficients are \(a_{0} = -47, a_{1} = 20, a_{2} = -2\) and the degree is 2.
1Step 1: Expand the given polynomial expression
First, we need to expand \((x-5)^{2}\). This can be done using the formula \((a-b)^2 = a^2 - 2ab + b^2\). Here, \(a=x\) and \(b=5\). So,
$$(x-5)^{2} = (x)^{2} - 2(x)(5) + (5)^{2} = x^2 - 10x + 25$$
Now, substitute this back into the given expression \(3-2(x-5)^{2}\):
$$3 - 2(x^2 - 10x + 25)$$
2Step 2: Distribute the -2
Now, distribute the -2 to each term in the parenthesis:
$$3 - 2x^2 + 20x - 50$$
3Step 3: Combine like terms
Combine the constants, 3 and -50:
$$-47 - 2x^2 + 20x$$
4Step 4: Write the polynomial in standard form
Rearrange the terms in decreasing powers of x and obtain:
$$-2x^2 + 20x - 47$$
5Step 5: Identify the coefficients and the degree of the polynomial
Now that we have the polynomial in standard form, we can easily identify the coefficients: \(a_{0} = -47, a_{1} = 20, a_{2} = -2\). Since the highest exponent of x is 2, the degree of the polynomial is 2.
Key Concepts
Standard FormCoefficientsDegree of Polynomial
Standard Form
When working with polynomials, one of the primary goals is to express them in what is known as "standard form." This form helps make polynomials easier to read and work with. The standard form of a polynomial is expressed in descending order of the exponents on the variable by using the format:
- \(a_{n} x^{n} + a_{n-1} x^{n-1} + \cdots + a_{1} x + a_{0}\)
- \(-2x^2 + 20x - 47\)
Coefficients
Coefficients in polynomials are the numbers that multiply the variable terms. They are crucial as they define the effect each term has on the polynomial's graph and shape. The standard form of a polynomial makes identifying coefficients simple. In our polynomial expression:
- \(-2x^2 + 20x - 47\)
- \(a_2 = -2\)
- \(a_1 = 20\)
- \(a_0 = -47\)
- \(-2\) is the coefficient of \(x^2\)
- \(20\) is the coefficient of \(x\)
- \(-47\) is the constant term, or the coefficient of \(x^0\)
Degree of Polynomial
One important aspect of polynomials is understanding their "degree," which tells you the highest power (exponent) of the variable in the polynomial. This degree determines the general shape and behavior of the graph and also gives insight into the potential number of solutions a polynomial equation may have.In the polynomial we considered, \(-2x^2 + 20x - 47\), the largest exponent of \(x\) is \(2\), thus the degree is \(2\).
- This implies that the polynomial is quadratic, typically represented by a parabola shaped graph when plotted.
- A degree of \(2\) suggests that the polynomial can have up to 2 roots or solutions.
Other exercises in this chapter
Problem 33
Write the polynomials in exercises in standard form $$a_{n} x^{n}+a_{n-1} x^{n-1}+\cdots+a_{1} x+a_{0}$$ What are the values of the coefficients \(a_{0}, a_{1},
View solution Problem 34
Without solving the equation, decide how many solutions it has. $$ (x-2) x=3(x-2) $$
View solution Problem 35
Without solving the equation, decide how many solutions it has. $$ \left(2-x^{2}\right)(x-4)(5-x)=0 $$
View solution Problem 35
Write the polynomials in exercises in standard form $$a_{n} x^{n}+a_{n-1} x^{n-1}+\cdots+a_{1} x+a_{0}$$ What are the values of the coefficients \(a_{0}, a_{1},
View solution