Problem 34
Question
Solve each equation using the addition property of equality. Be sure to check your proposed solutions. $$r+\frac{3}{5}=-\frac{7}{10}$$
Step-by-Step Solution
Verified Answer
The solution to the equation \(r+\frac{3}{5}=-\frac{7}{10}\) is \(r = -\frac{13}{10}\)
1Step 1: Isolate the variable 'r'
Subtract \(\frac{3}{5}\) from both sides of the equation. This will isolate the variable 'r'. This is done using the addition property of equality which states that we can add or subtract the same value from both sides of an equation and the equality will still hold. The operation gives \( r = -\frac{7}{10} - \frac{3}{5}\)
2Step 2: Calculate the value of 'r'
Calculate the right side of the expression by subtracting the fractions. \( -\frac{7}{10} - \frac{3}{5} = -\frac{7}{10} - \frac{6}{10} = -\frac{13}{10}\)
3Step 3: Check the solution
Substitute \(r = -\frac{13}{10}\) into the original equation to verify the solution. \[ r + \frac{3}{5} = -\frac{13}{10} + \frac{6}{10} = -\frac{7}{10}\] Since the left side equals the right side, the solution is correct.
Key Concepts
Solving Linear EquationsIsolating VariablesSubtracting FractionsEquation Verification
Solving Linear Equations
When we talk about solving linear equations, we mean finding the value of the variable that makes the equation true. The process usually involves a series of steps that can include adding, subtracting, multiplying, or dividing both sides of the equation by the same number.
In our example, the linear equation is in the form of a variable, in this case, 'r', plus a fraction equals a negative fraction. After applying operations equally on both sides, we can solve for the unknown variable. Solving linear equations is a fundamental skill in algebra, and understanding the principles behind it can help you tackle more complex mathematical problems.
In our example, the linear equation is in the form of a variable, in this case, 'r', plus a fraction equals a negative fraction. After applying operations equally on both sides, we can solve for the unknown variable. Solving linear equations is a fundamental skill in algebra, and understanding the principles behind it can help you tackle more complex mathematical problems.
Isolating Variables
Isolating variables is a crucial step in solving linear equations. The goal is to get the variable on one side of the equation by itself. To do this, we perform operations that 'undo' what is being done to the variable.
For instance, if a variable is being added by a number or another variable, we subtract that amount from both sides. Conversely, if a variable is being subtracted, we'd add. If the variable is being multiplied, we divide both sides, and if it's divided, multiply. Throughout these steps, we maintain the balance of the equation by doing the same thing to both sides, a principle known as the addition (or subtraction) property of equality, which allows us to isolate the variable and solves for it effectively.
For instance, if a variable is being added by a number or another variable, we subtract that amount from both sides. Conversely, if a variable is being subtracted, we'd add. If the variable is being multiplied, we divide both sides, and if it's divided, multiply. Throughout these steps, we maintain the balance of the equation by doing the same thing to both sides, a principle known as the addition (or subtraction) property of equality, which allows us to isolate the variable and solves for it effectively.
Subtracting Fractions
Common Denominators and Subtraction
The major step in subtracting fractions is finding a common denominator for the fractions involved. This means adjusting the fractions so that they both have the same bottom number. Once you have common denominators, you can easily subtract the numerators (the top numbers), and the common denominator remains the same.In the exercise given, we encountered fractions with denominators of 5 and 10. By converting the fractions to have a common denominator, which is 10 in this case, we are able to subtract the numerators easily. Remember, when working with negative signs, it's also important to pay attention to their proper placement to get the correct result.
Equation Verification
Once we think we've solved an equation, it's vital to verify our answer to ensure it is correct—this is what we call equation verification. To do this, we substitute our solution back into the original equation and check if both sides remain equal.
If they do, our solution is verified; if not, we may have made a mistake and need to review our steps. Equation verification is an essential part of problem-solving because it not only confirms the accuracy of our work but also reinforces our understanding of the underlying mathematical principles.
If they do, our solution is verified; if not, we may have made a mistake and need to review our steps. Equation verification is an essential part of problem-solving because it not only confirms the accuracy of our work but also reinforces our understanding of the underlying mathematical principles.
Other exercises in this chapter
Problem 33
Solve each equation and check your proposed solution in Exercises. Begin your work by rewriting each equation without fractions. $$\frac{2 x}{3}-5=7$$
View solution Problem 34
A rectangular field is five times as long as it is wide. If the perimeter of the field is 288 yards, what are the field's dimensions?
View solution Problem 34
Use the addition property of inequality to solve each inequality and graph the solution set on a number line. \(x-\frac{1}{3} \geq \frac{5}{6}\)
View solution Problem 34
Solve each equation in using both the addition and multiplication properties of equality. Check proposed solutions. $$-3 y+4=13$$
View solution