Problem 33
Question
Solve each equation and check your proposed solution in Exercises. Begin your work by rewriting each equation without fractions. $$\frac{2 x}{3}-5=7$$
Step-by-Step Solution
Verified Answer
The solution to the equation \(\frac{2 x}{3}-5=7\) is \(x = 18\).
1Step 1: Eliminate Fractions
In order to eliminate the fractions, one can multiply the whole equation by 3, which will make it a bit simpler. The equation becomes: \(3*(\frac{2 x}{3}) - 3*5 = 3*7\), or simplified: \(2x - 15 = 21\).
2Step 2: Isolate the Variable
Try to isolate x by adding 15 to both sides of the equation: \(2x - 15 + 15 = 21 + 15\), or simplified: \(2x = 36\).
3Step 3: Solve for Variable
Finally, divide both sides of the equation by 2, to solve for x, as such: \(\frac{2x}{2} = \frac{36}{2}\), which gives: \(x = 18\).
4Step 4: Check Solution
Check the solution by substituting \(x = 18\) back into the original equation, this would give: \(\frac{2 * 18}{3} - 5\), which simplifies to \(12 - 5 = 7\), so the solution is correct.
Key Concepts
Solving EquationsFractions in EquationsVariable Isolation
Solving Equations
To solve algebraic equations, we follow systematic steps to find the value of the unknown, often represented by a variable like \(x\). The goal is to make sure both sides of the equation are balanced and equivalent.
Generally, here’s an approach you can adopt:
Generally, here’s an approach you can adopt:
- First, simplify both sides of the equation as much as possible by performing any obvious arithmetic operations.
- Next, aim at making the variable stand alone on one side by "undoing" what is done to it through mathematical operations like addition, subtraction, multiplication, or division.
- Finally, verify your solution by substituting it back into the original equation. This ensures no mistakes were made during the process.
Fractions in Equations
Fractions can often make solving equations seem tricky, but they can be managed easily by eliminating them. This is done by finding the denominator and multiplying the entire equation by it, which helps in handling the fraction components smoothly.
For instance, if you have an equation like \(\frac{2x}{3} - 5 = 7\), to eliminate the fraction, we multiply all terms in the equation by 3 (the denominator of the fraction). This leads to the new equation: \(2x - 15 = 21\).
For instance, if you have an equation like \(\frac{2x}{3} - 5 = 7\), to eliminate the fraction, we multiply all terms in the equation by 3 (the denominator of the fraction). This leads to the new equation: \(2x - 15 = 21\).
- Multiplying an equation by the denominator makes the fraction disappear, simplifying the entire equation.
- Always multiply every term on both sides to maintain the balance of the equation.
- Once the fractions are gone, solving the equation becomes much more straightforward.
Variable Isolation
Isolating the variable is a fundamental skill in solving equations. It involves transforming the equation to get the variable alone on one side. This process signifies finding the value of the variable that makes the equation true.
In our example, once the fraction is removed, the equation is \(2x - 15 = 21\). To isolate \(x\), we start by reversing the subtraction with an addition: add 15 on both sides to get \(2x = 36\).
In our example, once the fraction is removed, the equation is \(2x - 15 = 21\). To isolate \(x\), we start by reversing the subtraction with an addition: add 15 on both sides to get \(2x = 36\).
- Perform the same operation on both sides to maintain the equation's balance.
- Reverse the operation of multiplication by dividing each side by 2, resulting in \(x = 18\).
- The goal of this process is to have the variable, by itself, on one side of the equation.
Other exercises in this chapter
Problem 33
Solve each equation in using both the addition and multiplication properties of equality. Check proposed solutions. $$-2 y+5=7$$
View solution Problem 33
Use the percent formula, \(A=P B: A\) is \(P\) percent of \(B,\) to solve. \(24 \%\) of what number is \(40.8 ?\)
View solution Problem 34
A rectangular field is five times as long as it is wide. If the perimeter of the field is 288 yards, what are the field's dimensions?
View solution Problem 34
Solve each equation using the addition property of equality. Be sure to check your proposed solutions. $$r+\frac{3}{5}=-\frac{7}{10}$$
View solution