Problem 33
Question
We have two equal-size boxes, \(A\) and \(B\) . Each box contains gas that behaves as an ideal gas. We insert a thermometer into each box and find that the gas in box \(A\) is at a temperature of \(50^{\circ} \mathrm{C}\) while the gas in box \(B\) is at \(10^{\circ} \mathrm{C}\) . This is all we know about the gas in the boxes. Which of the following statements must be true? Which could be true? (a) The pressure in \(A\) is higher than in \(B\) . (b) There are more molecules in \(A\) than in \(B\) . (c) \(A\) and \(B\) do not contain the same type of gas. (d) The molecules in \(A\) have more average kinetic energy per molecule than those in \(B\) . (e) The molecules in \(A\) are moving faster than those in \(B .\) Explain the reasoning behind your answers.
Step-by-Step Solution
VerifiedKey Concepts
Thermodynamics
- The ideal gas law is expressed as \(PV = nRT\), where \(P\) is pressure, \(V\) is volume, \(n\) is the number of moles, \(R\) is the gas constant, and \(T\) is the absolute temperature in Kelvin.
- It demonstrates the direct proportionality between pressure and temperature, suggesting that for a constant volume and amount of gas, as the temperature rises, the pressure also increases.
- This principle is crucial for understanding that high temperature in a gas can lead to higher pressure, as seen in many practical thermodynamic systems like engines and refrigerators.
Kinetic Theory of Gases
- According to this theory, gas molecules are in constant random motion, colliding with one another and with the walls of their container. These collisions result in gas pressure.
- Temperature, in this context, is a measure of the average kinetic energy of the molecules in the gas. Therefore, higher temperatures mean higher average speeds and more energetic particle movement.
- The average kinetic energy per molecule is captured in the expression \(\frac{3}{2}kT\), where \(k\) is the Boltzmann constant and \(T\) is the temperature in Kelvin.
Temperature Conversion
- Kelvin is the standard unit of temperature in science because it begins at absolute zero, the point where all molecular motion theoretically stops.
- To convert from Celsius to Kelvin, simply add 273.15 to the Celsius temperature. So for box A, \(50^{\circ}C = 323.15 \, K\) and for box B, \(10^{\circ}C = 283.15 \, K\).
- Using Kelvin allows for direct correlation with energy and kinetic theories since Kelvin directly links to molecular kinetic energy and movement.