Problem 31
Question
Gaseous Diffusion of Uranium. (a) A process called gaseous diffusion is often used to separate isotopes of uranium that is, atoms of the elements that have different masses, such as 235 \(\mathrm{U}\) and 238 \(\mathrm{U} .\) The only gaseous compound of uranium at ordinary temperatures is uranium hexafluoride, UF \(_{6}\) . Speculate on how 235 \(\mathrm{UF}_{6}\) and \(^{238} \mathrm{UF}_{6}\) molecules might be separated by diffusion. (b) The molar masses for \(^{235} \mathrm{UF}_{6}\) and 238 \(\mathrm{UF}_{6}\) molecules are 0.349 \(\mathrm{kg} / \mathrm{mol}\) and \(0.352 \mathrm{kg} / \mathrm{mol},\) respectively. If uranium hexafluoride acts as an ideal gas, what is the ratio of the root-meansquare speed of \(^{235} \mathrm{UF}_{6}\) molecules to that of \(^{238} \mathrm{UF}_{6}\) molecules if the temperature is uniform?
Step-by-Step Solution
VerifiedKey Concepts
Uranium Isotopes
Both isotopes are crucial, especially in nuclear energy and weaponry, due to their differing nuclear properties. In industry, separating uranium isotopes is vital for enriching uranium, often for use in nuclear reactors or weapons. Gaseous diffusion is one method employed, relying on the slight mass difference between isotopes.
Uranium hexafluoride (UF$_6$) is used in this process because it is the only gaseous compound of uranium at usable temperatures. Diffusion exploits the principle that lighter molecules ( 235 UF$_6$) diffuse faster than heavier molecules ( 238 UF$_6$). This difference allows for the physical separation of isotopes.
Root-Mean-Square Speed
The RMS speed, \(v_{rms}\), for gas molecules is calculated using the formula:\[v_{rms} = \sqrt{\frac{3kT}{m}}\]where \(k\) is the Boltzmann constant, \(T\) is the temperature in Kelvin, and \(m\) is the molar mass of the gas molecules in kilograms per mole.In the context of uranium isotope separation, because temperature \(T\) is uniform, \(v_{rms}\) is determined by the molar mass. Thus, lighter molecules (235UF\(_6\)) will have a slightly higher RMS speed compared to heavier molecules (238UF\(_6\)).
It is this principle that allows gaseous diffusion to be an effective method for isotope separation.
Molecular Mass
The molecular mass determines how quickly a molecule can move under set conditions, like temperature and pressure, due to inertia. For uranium hexafluoride, $^{235}$ UF$_6$ has a marginally lower molar mass (0.349 kg/mol) compared to $^{238}$ UF$_6$ (0.352 kg/mol). This small difference plays a significant role in diffusion processes. Since lighter molecules have less inertia, they diffuse quicker. Therefore, even a minor variation in molecular mass can effectively separate isotopes through gaseous diffusion, as observed in the operation scale of uranium enrichment. Understanding and calculating molecular masses are crucial steps in predicting and exploiting gas behavior—which is essential for practical applications like isotope separation.