Problem 32
Question
Use the General Power Rule to find the derivative of the function. $$ g(x)=\sqrt{5-3 x} $$
Step-by-Step Solution
Verified Answer
The derivative of the function \(g(x) = \sqrt{5 - 3x}\) is \(g'(x) = - (3 / 2\sqrt{5 - 3x})\).
1Step 1: Express the Function as a Power of x
Rewrite the function \(g(x) = \sqrt{5 - 3x}\) as \(g(x) = (5 - 3x)^{1/2}\). This way, it aligns better with the general power rule. Here \(u = 5 - 3x\) and \(n = 1/2\).
2Step 2: Apply the General Power Rule
Using the general power rule, \(d/dx(u^n) = nu^{n-1}u'\), apply it to the function. But first find \(u'\), the derivative of \(u = 5 - 3x\). The derivative \(u' = -3\). Now apply the general power rule which yields \(1/2*(5 - 3x)^{(1/2)-1}*(-3)\).
3Step 3: Simplify the Expression
Simplify the expression obtained in the previous step. The expression then becomes \(-(3/2)(5 - 3x)^{-1/2}\).
4Step 4: Return to Original Form
The last step involves rewriting the derivative back to the radical form since the original function was given in that form. The derivative \(g'(x)\) becomes \(- (3 / 2\sqrt{5 - 3x})\)
Key Concepts
DerivativeFunction NotationExponent RulesRadical Expression
Derivative
The derivative of a function is a fundamental concept in calculus, representing the rate at which the function's value changes as its input changes.
For any given function, the derivative tells us how steep the function's graph is at any point along its curve. This provides valuable insights into the behavior of the function, such as its increasing or decreasing trends and any points where it flattens or turns around.
For any given function, the derivative tells us how steep the function's graph is at any point along its curve. This provides valuable insights into the behavior of the function, such as its increasing or decreasing trends and any points where it flattens or turns around.
- In calculus, the notation for the derivative of a function is typically written as \( f'(x) \) or \( \frac{df}{dx} \).
- Finding a derivative involves applying specific rules and techniques based on the form of the function.
Function Notation
Function notation is a way to denote functions in a compact and clear manner.
In functions, we often use symbols such as \( f(x) \) to describe the function's rule, in terms of the variable \( x \).
In functions, we often use symbols such as \( f(x) \) to describe the function's rule, in terms of the variable \( x \).
- For instance, in the given function \( g(x) = \sqrt{5-3x} \), "\( g(x) \)" simply refers to the function named "g" evaluated at the input "x".
- This way of writing functions is useful because it instantly communicates both the function itself and the variable it's being evaluated with.
Exponent Rules
Understanding exponent rules is key to rewriting and differentiating functions, especially when they involve roots or powers.
Exponents are a shorthand way to represent repeated multiplication or division. Some of the fundamental rules include:
Exponents are a shorthand way to represent repeated multiplication or division. Some of the fundamental rules include:
- \((a^m)(a^n) = a^{m+n}\) - multiplying like bases adds their exponents.
- \((a^m)/(a^n) = a^{m-n}\) - dividing like bases subtracts the exponents.
- \((a^m)^n = a^{m*n}\) - raising a power to a power multiplies the exponents.
Radical Expression
A radical expression includes roots such as square roots, cube roots, etc.
Radicals often appear in different forms in mathematics, and they're closely related to exponentiation, where, for example, the square root of a number can be represented as that number raised to the power of \( 1/2 \).
Radicals often appear in different forms in mathematics, and they're closely related to exponentiation, where, for example, the square root of a number can be represented as that number raised to the power of \( 1/2 \).
- Radicals can complicate expressions unless converted to exponents for ease of differentiation or integration.
- In the context of calculus and finding derivatives, radicals are commonly rewritten using exponent rules.
Other exercises in this chapter
Problem 32
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