Problem 32
Question
Graph all solutions on a number line and give the corresponding interval notation. $$ x<12 \text { or } x>-6 $$
Step-by-Step Solution
Verified Answer
The solution in interval notation is (-6, 12).
1Step 1: Analyze the Inequalities Separately
There are two separate inequalities to consider: 1. \( x < 12 \) 2. \( x > -6 \) These inequalities describe two sets of solutions on the number line.
2Step 2: Graph Each Inequality
For \( x < 12 \), draw an open circle at 12 and shade the number line to the left to indicate all numbers less than 12. For \( x > -6 \), draw an open circle at -6 and shade the number line to the right to indicate all numbers greater than -6.
3Step 3: Combine the Solutions
Since the solutions form an 'or' inequality, any number that satisfies at least one of the inequalities is part of the solution set. Thus, draw a number line with combined shading from both previous steps:
- From the open circle at -6, shade all numbers to the right, combining with the shading for numbers less than 12.
4Step 4: Write the Solution in Interval Notation
In interval notation, the solution is written by combining both intervals. The numbers range from all numbers greater than -6 to numbers less than 12. In interval notation, this is written as: \((-6, 12)\).
Key Concepts
Number LineInterval NotationOpen Circle
Number Line
A number line is a visual tool that helps us understand inequalities and their solutions. It is a straight line that displays numbers in increasing order from left to right. When graphing inequalities on a number line, we represent solutions with shaded regions and specific symbols.
For inequalities like \(x < 12\) or \(x > -6\), you will:
For inequalities like \(x < 12\) or \(x > -6\), you will:
- Draw the line with an appropriate scale.
- Plot points for the boundary values. Here, you place points at 12 and -6.
- Use arrows to indicate extending solutions beyond visible values.
Interval Notation
Interval notation is a concise way to describe a range of numbers, often used to express the solutions of inequalities. This method uses brackets to show whether endpoints are included or not.
For the inequality \(x < 12\) or \(x > -6\), the solution is the range of numbers greater than -6 and less than 12. We write this as \((-6, 12)\) in interval notation.
For the inequality \(x < 12\) or \(x > -6\), the solution is the range of numbers greater than -6 and less than 12. We write this as \((-6, 12)\) in interval notation.
- Parentheses \(()\) mean the endpoint is not included.
- Brackets \([]\) mean the endpoint is included.
Open Circle
The open circle is an important symbol used on number lines to denote that a point is not included in the solution set of an inequality.
When you see a statement like \(x < 12\) or \(x > -6\), they indicate that 12 and -6 themselves are not part of the solution.
To use open circles:
When you see a statement like \(x < 12\) or \(x > -6\), they indicate that 12 and -6 themselves are not part of the solution.
To use open circles:
- For \(x < 12\), place an open circle at 12. This shows values approaching 12, not 12 itself.
- For \(x > -6\), place an open circle at -6, indicating values greater than -6 but not -6 itself.
Other exercises in this chapter
Problem 32
Subtract \(x-3\) from twice the quantity \(x-1\).
View solution Problem 32
Solve and graph the solution set. In addition, present the solution set in interval notation. $$ 12 x-4(3 x+5) \leq-2 $$
View solution Problem 32
A larger integer is 7 less than twice a smaller integer. If the two integers have a ratio of 2 to 3 find the integers.
View solution Problem 32
Set up an algebraic equation and then solve. The difference between twice the larger of two consecutive odd integers and the smaller is \(59 .\) Find the intege
View solution