Problem 32
Question
For the following problems, write each of the quantities using exponential notation. $$ (2 y)(2 y) 2 y 2 y $$
Step-by-Step Solution
Verified Answer
Answer: The exponential notation of the given expression is \(16y^4\).
1Step 1: Identify the common terms and their exponents
In the given expression \((2y)(2y)2y2y\), we can see that there are 4 copies of the term \(2y\). Each of these terms are being multiplied together.
2Step 2: Express the product as an exponent
Since we have 4 copies of the term \(2y\), we can express this as a single term raised to a power of 4:
$$
(2y)^4
$$
3Step 3: Apply rules of exponents
Since we have each of the terms inside the parenthesis raised to an exponent, we can apply the rules of exponents to find the final form:
$$
(2^4)(y^4)
$$
4Step 4: Calculate the final result
Finally, we compute 2 raised to the power of 4:
$$
(16)(y^4)
$$
Thus, the given expression can be written in exponential notation as:
$$
16y^4
$$
Key Concepts
Exponent RulesIdentifying Common TermsMultiplication of Variables
Exponent Rules
Understanding exponent rules is essential for simplifying expressions. Exponents, often referred to as powers or indices, are a way of expressing repeated multiplication of a number by itself. For example, in the expression \((2)^4\), the number 2 is the base, and 4 is the exponent. It signifies that 2 should be multiplied by itself 4 times, which calculates to 16. There are several key rules you should remember about exponents:
- Product of Powers Rule: If you multiply the same bases, add their exponents, such as \(a^m \times a^n = a^{m+n}\).
- Power of a Power Rule: If you have an exponent raised to another exponent, multiply the exponents, \((a^m)^n = a^{m \cdot n}\).
- Power of a Product Rule: Distribute the exponent to each factor inside the parentheses, \((ab)^n = a^n \times b^n\).
- Zero Exponent Rule: Any nonzero number raised to the 0 power is 1, like \(a^0 = 1\).
Identifying Common Terms
Identifying common terms in an expression involves recognizing which factors appear repeatedly. This skill is crucial because it allows us to simplify calculations by using exponential notation.In the problem \((2y)(2y)2y2y\), it's clear that the term \(2y\) appears four times in total. When you realize that the same element is repeated, you can use it as a single base raised to the power equal to its occurrences. Recognizing common terms streamlines the simplification process with the power of exponents. This not only makes expressions more concise but also sets the stage for applying more complex operations with ease.
Multiplication of Variables
Multiplication of variables follows similar rules to those of numbers. When variables are multiplied together, their exponents can be combined if the bases are the same.In an expression, such as \((2y)^4\), both the number 2 and the variable \(y\) are separately being multiplied. Here’s how you could break it down:
- First, recognize \((2y)^4\) as \((2^4)\cdot(y^4)\). This means each factor inside the parenthesis is raised to the power of 4.
- Compute \(2^4\) which results in 16.
- The \(y\) has its own exponent which is 4, showing that \(y\) is multiplied by itself four times (\(y \cdot y \cdot y \cdot y\)). This simplifies to \(y^4\).
Other exercises in this chapter
Problem 32
Use the product rule and quotient rule of exponents to simplify the following problems. Assume that all bases are nonzero and that all exponents are whole numbe
View solution Problem 32
Use the power rules for exponents to simplify the following problems. Assume that all bases are nonzero and that all variable exponents are natural numbers. $$
View solution Problem 32
For the pairs of real numbers shown in the following problems, write the appropriate relation symbol \((,=)\) in place of the \(*\) $$-3 * 0$$
View solution Problem 32
For the following problems, use the order of operations to find each value. $$\left(\frac{5}{12}-\frac{1}{4}\right)+\left(\frac{1}{6}+\frac{2}{3}\right)$$
View solution