Problem 32
Question
Exer. 31-32: Complete the statements. (a) As \(x \rightarrow 1^{-}, \sin ^{-1} x \rightarrow\) (b) As \(x \rightarrow-1^{+}, \cos ^{-1} x \rightarrow\) (c) As \(x \rightarrow-\infty, \tan ^{-1} x \rightarrow\)
Step-by-Step Solution
Verified Answer
(a) \(\pi/2\); (b) \(\pi\); (c) \(-\pi/2\)."
1Step 1: Evaluate the Limit of Inverse Sine Function
As \(x \to 1^-\), the value of \(\sin^{-1} x \) approaches the angle whose sine is approaching 1 from the negative side. The angle whose sine is 1 is \(\frac{\pi}{2}\). Thus, \(\sin^{-1} x \to \frac{\pi}{2}\) as \(x \to 1^-\).
2Step 2: Evaluate the Limit of Inverse Cosine Function
As \(x \to -1^+\), the value of \(\cos^{-1} x \) approaches the angle whose cosine is approaching -1 from the positive direction. The angle whose cosine is -1 is \(\pi\). Therefore, \(\cos^{-1} x \to \pi\) as \(x \to -1^+\).
3Step 3: Evaluate the Limit of Inverse Tangent Function
As \(x \to -\infty\), the value of \(\tan^{-1} x \) approaches the angle whose tangent value becomes increasingly negative. The angle for which this is true is \(-\frac{\pi}{2}\). Therefore, \(\tan^{-1} x \to -\frac{\pi}{2}\) as \(x \to -\infty\).
Key Concepts
Limits of Trigonometric FunctionsInverse SineInverse CosineInverse Tangent
Limits of Trigonometric Functions
Limits of trigonometric functions involve understanding how these functions behave as the variable approaches certain points or infinity. This is crucial for calculating the limits of inverse trigonometric functions.
Inverse trigonometric functions often involve angles where the original trigonometric functions are evaluated.
Inverse trigonometric functions often involve angles where the original trigonometric functions are evaluated.
- Sine: As value approaches 1, the limit is \(\frac{\pi}{2}\)
- Cosine: As value approaches -1, the limit is \(\pi\)
- Tangent: As value approaches negative infinity, the limit is \(-\frac{\pi}{2}\)
Inverse Sine
The inverse sine function, denoted as \(\sin^{-1} x\), tells us the angle whose sine is x. This function is pivotal in trigonometry and calculus, especially when solving equations involving angles and arcs.
For the range of \(\sin^{-1} x\):
For the range of \(\sin^{-1} x\):
- The function takes input from \(-1\) to \(1\)
- The output, which is the angle, ranges from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\)
Inverse Cosine
The inverse cosine function, noted as \(\cos^{-1} x\), gives the angle whose cosine value is x. This inverse is essential in trigonometry for calculating angles from cosine values.
The range of \(\cos^{-1} x\):
The range of \(\cos^{-1} x\):
- The input range is from \(-1\) to \(1\)
- The output angle ranges from 0 to \(\pi\)
Inverse Tangent
The inverse tangent function, represented as \(\tan^{-1} x\), identifies the angle whose tangent equals x. It's useful in scenarios requiring conversion from slope to angle, for instance, in navigation and physics.
For \(\tan^{-1} x\):
For \(\tan^{-1} x\):
- This function accepts input from negative to positive infinity
- The resulting angles lie within the interval \((-\frac{\pi}{2}, \frac{\pi}{2})\)
Other exercises in this chapter
Problem 31
Exer. 25-36: Verify the reduction formula. $$ \cos \left(x+\frac{3 \pi}{2}\right)=\sin x $$
View solution Problem 31
Express in terms of the cosine function with exponent \(1 .\) $$ \cos ^{4} \frac{\theta}{2} $$
View solution Problem 32
Exer. 1-38: Find all solutions of the equation. $$ (2 \sin u-1)(\cos u-\sqrt{2})=0 $$
View solution Problem 32
Exer. 1-50: Verify the identity. $$ (a \cos t-b \sin t)^{2}+(a \sin t+b \cos t)^{2}=a^{2}+b^{2} $$
View solution