Problem 32
Question
Begin by graphing the absolute value function, \(f(x)=|x| .\) Then use transformations of this graph to graph the given function. $$ g(x)=-|x+4|+2 $$
Step-by-Step Solution
Verified Answer
The graph of function \(g(x)=-|x+4|+2\) is a 'V' shape that opens downward, shifted 4 units to the left and 2 units up from the origin, such that its lowest point is at (-4,2).
1Step 1: Understanding the basic function
Start by graphing the function \(f(x) = |x|\). This is a V-shaped graph that intersects the origin (0,0) and slopes upwards on either side.
2Step 2: Identifying transformations
In the transformed function \(g(x)=-|x+4|+2\), three transformations can be identified: 1) A reflection on the x-axis due to the 'negative' introduced; 2) A horizontal shift to the left by 4 units represented by '+4' inside the absolute value; 3) A vertical shift upwards by 2 units represented by '+2' outside the absolute value.
3Step 3: Applying transformations to the graph
Now apply these transformations to the initial graph of \(f(x)=|x|\). Because of the reflection, the 'V' that used to open upwards will now open downwards. The horizontal shift will move the lowest point of the 'V' from the origin to the point (-4,0). Lastly, with the upward shift of 2 units, this lowest point will move to (-4,2).
Key Concepts
Graph TransformationsReflection on the x-axisVertical and Horizontal ShiftsGraphing Techniques
Graph Transformations
Graph transformations are changes made to the basic graph of a function, altering its appearance without changing its overall shape. These changes can vary, including shifts, reflections, and stretching or compressing the graph. Understanding graph transformations is crucial for students learning algebra and calculus, as it allows us to visualize complex equations more easily.
- Each transformation affects the position or orientation of the graph in a specific way.
- Analyzing transformations involves breaking down the equation into parts to determine which transformation occurs.
Reflection on the x-axis
A reflection on the x-axis means that the graph is flipped over the horizontal axis. This operation effectively changes the direction in which the graph opens. For the absolute value function, this reflection is induced by adding a negative sign in front of the absolute value.
- If you initially have \(f(x) = |x|\), reflecting it along the x-axis turns it into \(-|x|\).
- Visualize this as taking each point on the graph and mirroring it directly over the x-axis.
Vertical and Horizontal Shifts
Vertical and horizontal shifts move the entire graph without altering its shape or orientation. These shifts help position the graph at its final location on the coordinate plane.
- A horizontal shift happens when a constant is added or subtracted inside the absolute value symbols. For example, \(f(x) = |x + 4|\) shifts the graph 4 units left.
- A vertical shift occurs when a constant is added or subtracted outside the absolute value function. For instance, in \(g(x) = |x| + 2\), the graph moves up 2 units.
- A horizontal shift left by 4 units (adjusting the vertex to \(-4\))
- A vertical shift up by 2 units (raising the vertex to an overall point of \(-4, 2\))
Graphing Techniques
Graphing techniques are methods used to accurately plot functions using transformations and other algebraic tools. These techniques streamline the process of drawing function graphs and make it easier to understand the influence of each parameter on a function.
- Start with the basic graph (e.g., \(f(x) = |x|\)).
- Apply transformations one by one—first reflection, then shifts, etc.
- Check key points like the vertex and intercepts to verify accuracy.
- Reflect it to open downwards using the negative sign.
- Shift it horizontally by 4 units left, landing the vertex at \((-4, 0)\).
- Then, move it up 2 units to finalize the vertex at \((-4, 2)\).
Other exercises in this chapter
Problem 31
In Exercises \(21-32,\) evaluate each function at the given values of the independent variable and simplify. $$f(x)=\frac{x}{|x|}$$ a. \(f(6)\) b. \(f(-6)\) c.
View solution Problem 31
Write the standard form of the equation of the circle with the given center and radius. $$ \text { Center }(0,0), r=7 $$
View solution Problem 32
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Passing through \((-3,6)\) and \((3,-2)\)
View solution Problem 32
Find: a. \((f \circ g)(x)\) b. the domain of \(f \circ g\) $$f(x)=\frac{x}{x+5}, g(x)=\frac{6}{x}$$
View solution