Problem 31
Question
Write the standard form of the equation of the circle with the given center and radius. $$ \text { Center }(0,0), r=7 $$
Step-by-Step Solution
Verified Answer
The standard form of the equation of the circle with center at the origin (0,0) and radius 7 is \(x^2 + y^2 = 49\).
1Step 1: Identify values
Given in the exercise, the center of the circle is at the origin (0,0) and the radius \(r\) is 7.
2Step 2: Apply values to standard form
Substitute the given center coordinates and radius into the standard form of a circle equation which is \((x-a)^2 + (y-b)^2 = r^2\). Since the center is (0,0), \(a = 0\) and \(b = 0\). The radius \(r = 7\). Hence the circle equation becomes \(x^2 + y^2 = 49\).
Key Concepts
Standard FormCenter of a CircleRadius of a CircleOrigin
Standard Form
In geometry, the standard form of a circle's equation is a compact way to express all circles on a coordinate plane. This form provides vital details such as the center and radius at a glance. The standard form of the equation for a circle is \((x-a)^2 + (y-b)^2 = r^2\). Here,
- \(a\) and \(b\) denote the coordinates of the center of the circle \((a,b)\).
- \(r\) is the radius of the circle.
Center of a Circle
The center of a circle is a crucial element as it determines the position of the circle on a plane. The point \((a, b)\) in the equation \((x-a)^2 + (y-b)^2 = r^2\) identifies the exact center. In practical terms, it tells us how far the circle is from the origin of the coordinate plane's axes.Understanding the center is vital when graphing the circle, as it acts as the midpoint from which the radius extends in all directions. The center does not have to be at the origin; it can be at any point on the plane, allowing diverse placement of the circle.
Radius of a Circle
The radius of a circle is the fixed distance from its center to any point on the perimeter of the circle. In the standard form equation, it appears as \(r^2\). Thus, if you know \(r^2\), you find the radius \(r\) by taking the square root. For example, if the equation is \(x^2 + y^2 = 49\), the radius is \(r = \sqrt{49} = 7\). The significance of the radius lies in its consistent length from the center, which dictates the circle's size. A larger radius means a bigger circle, and vice versa. The radius is always positive.
Origin
The origin is the point \((0, 0)\) on a coordinate plane where the x-axis and y-axis intersect. It's the foundational point of reference in graphing. When a circle's center is at the origin, the equation simplifies beautifully into a more basic form because both \(a\) and \(b\) are zero. This gives us the equation \(x^2 + y^2 = r^2\) for a circle centered at the origin. This simplicity aids significantly in visualization and calculations. Points directly on the axes have immediate relationships with the origin since the horizontal and vertical distances directly reflect the radius.
Other exercises in this chapter
Problem 31
Find: a. \((f \circ g)(x)\) b. the domain of \(f \circ g\) $$f(x)=\frac{x}{x+1}, g(x)=\frac{4}{x}$$
View solution Problem 31
In Exercises \(21-32,\) evaluate each function at the given values of the independent variable and simplify. $$f(x)=\frac{x}{|x|}$$ a. \(f(6)\) b. \(f(-6)\) c.
View solution Problem 32
Begin by graphing the absolute value function, \(f(x)=|x| .\) Then use transformations of this graph to graph the given function. $$ g(x)=-|x+4|+2 $$
View solution Problem 32
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Passing through \((-3,6)\) and \((3,-2)\)
View solution