Problem 31
Question
Write an equation of an ellipse for the given foci and co-vertices. foci \(( \pm 14,0),\) co-vertices \((0, \pm 7)\)
Step-by-Step Solution
Verified Answer
The equation of the ellipse is \(\frac{x^2}{225} + \frac{y^2}{49} = 1\)
1Step 1: Identify a, b and c Values
We know that the foci of the ellipse are located at \(\pm 14,0\), thus, c = 14. The co-vertices of the ellipse are located at \(0,\pm 7\), thus, b = 7. As the foci lies on the x-axis, and the foci are further from the center than the co-vertices, the major axis must be the x-axis, hence a = c.
2Step 2: Find value of a
We can find the value for a using the relationship \(c = \sqrt{a^2 - b^2}\), so \(a = \sqrt{c^2 + b^2} = \sqrt{14^2 + 7^2} = 15\).
3Step 3: Write the equation of ellipse
The equation of an ellipse in standard form with a major axis on the x-axis is \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\). Substituting the values a = 15 and b = 7 in the equation, the equation of the ellipse is \(\frac{x^2}{15^2} + \frac{y^2}{7^2} = 1\).
Key Concepts
Understanding Foci of an EllipseThe Role of Co-Vertices in an EllipseDefining the Major Axis of an Ellipse
Understanding Foci of an Ellipse
An ellipse is a fascinating shape in mathematics defined by two special points called "foci" (plural of focus). These points, denoted in this problem as \((\pm 14,0)\), have a unique property: any point on the ellipse has a combined distance to these foci that is constant.
The positions of the foci give a lot of insight into the shape's overall dimensions. They help determine the length of the ellipse along its major axis.
The positions of the foci give a lot of insight into the shape's overall dimensions. They help determine the length of the ellipse along its major axis.
- If the foci are along the x-axis, the major axis is horizontal.
- If the foci are along the y-axis, the major axis is vertical.
The Role of Co-Vertices in an Ellipse
Co-vertices are points that signify the ends of the minor axis in an ellipse. In this problem, they are given as \((0, \pm 7)\). Co-vertices help define the width of the ellipse.
While the foci provide information about the major axis, the co-vertices give clarity about the minor axis, helping you understand the shorter dimension of the ellipse.
While the foci provide information about the major axis, the co-vertices give clarity about the minor axis, helping you understand the shorter dimension of the ellipse.
- Co-vertices are always perpendicular to the foci.
- They indicate the length of the ellipse along the minor axis.
Defining the Major Axis of an Ellipse
The major axis is an essential component of an ellipse, representing the longest diameter and passing through both foci. In this scenario, since the foci \((\pm 14,0)\) lie on the x-axis, the major axis is the horizontal one.
The length of the major axis is determined by the variable \(a\), which is solved through the relationship \(c = \sqrt{a^2 - b^2}\). In this equation:
This means our major axis extends 15 units in each direction from the center, along the x-axis.
The length of the major axis is determined by the variable \(a\), which is solved through the relationship \(c = \sqrt{a^2 - b^2}\). In this equation:
- \(a\) = length from the center to the end of the ellipse on the major axis.
- \(c\) = distance from the center to a focus.
- \(b\) = length from the center to the end on the minor axis.
This means our major axis extends 15 units in each direction from the center, along the x-axis.
Other exercises in this chapter
Problem 30
Graph each equation. Describe the graph and its lines of symmetry. Then find the domain and range. $$ 11 x^{2}+11 y^{2}=44 $$
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Use the center and the radius to graph each circle. $$ (x-1)^{2}+(y+3)^{2}=16 $$
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Write an equation for each conic section. Then sketch the graph. parabola with vertex \((2,-3)\) and focus \((2,5)\)
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Identify the vertex, the focus, and the directrix of each graph. Then sketch the graph. $$ -8 x=y^{2} $$
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