Problem 31
Question
Identify the vertex, the focus, and the directrix of each graph. Then sketch the graph. $$ -8 x=y^{2} $$
Step-by-Step Solution
Verified Answer
The vertex is at (0,0), the focus is at (-2, 0), and the directrix is the line \( x = 2 \).
1Step 1: Understand Parabolic Form
A horizontal parabola equation is in the form \( 4p(x - h) = (y - k)^2 \), where \( (h, k) \) is the vertex. In this case, we can rewrite our equation as \( x = -1/8 * y^2 \)
2Step 2: Identify the Vertex
In our equation, \( h = 0 \) and \( k = 0 \). Thus, the vertex of the parabola is at the origin, (0,0).
3Step 3: Identify the Focus
The distance from vertex to the focus is given by \( p \) in \( 4p = -8 \), so \( p = -2 \). Since this is a parabola opening to the left, we subtract \( p \) from the \( x \) coordinate of the vertex to get the focus which is (-2, 0).
4Step 4: Identify the Directrix
The directrix line equation for a leftward opening parabola is \( x = h + p \). Replacing \( h = 0 \) and \( p = -2 \), we get the directrix equation as \( x = 2 \).
5Step 5: Sketch the Graph
Once the vertex, focus, and directrix are determined, graph the parabola with these elements by plotting the vertex first at point (0,0), add the focus at (-2,0) and draw the directrix line at \( x = 2 \). The parabola opens to the left, with the focus being inside the parabola and directrix line being on the right.
Key Concepts
VertexFocusDirectrix
Vertex
When dealing with parabolas, the vertex is a crucial point. It's where the parabola either reaches its maximum or minimum value, tipping directions. For a parabola like the one given in the equation \[-8x = y^2\], it's expressed in the form \[4p(x - h) = (y - k)^2\].Here, \((h, k)\) represents the vertex of the parabola.
In this specific case, the equation can be rewritten to match the standard form, revealing that both \(h\) and \(k\) are zero. This means the vertex is right at the origin, \((0,0)\).
In this specific case, the equation can be rewritten to match the standard form, revealing that both \(h\) and \(k\) are zero. This means the vertex is right at the origin, \((0,0)\).
- The position of the vertex helps in determining the placement of the rest of the parabola.
- Knowing the vertex is vital as it's the starting point for graphing the rest of the elements.
Focus
The focus is another essential feature of a parabola. It's a point inside the parabola that, along with the directrix, defines its shape.To find the focus, first identify the value \(p\) in the equation \[4p = -8\], so \(p = -2\). Since the parabola opens to the left, this affects where the focus is located.
The focus for a leftward-facing parabola is shy away in the same direction as the opening.For this equation, the focus is shifted negatively along the x-axis from the vertex, resulting in the point \((-2,0)\).
The focus for a leftward-facing parabola is shy away in the same direction as the opening.For this equation, the focus is shifted negatively along the x-axis from the vertex, resulting in the point \((-2,0)\).
- Determining \(p\) is crucial in ensuring the focus is in the correct position relative to the vertex.
- The focus is internal to the parabola, helping to define its directional opening.
Directrix
The directrix is a straight line that complements the focus to help shape a parabola. It's not a part of the parabola but plays a magic role alongside the focus to guide the structure.To find the directrix for the parabola, use the formula \[x = h + p\]. With \(h = 0\) and \(p = -2\), calculate it as \[x = 2\], placing it on the positive side of the x-axis.
- The directrix is parallel to the y-axis in this orientation, enforcing the parabolic shape.
- Ensures a consistent distance from the vertex and focus with respect to the parabola's structure.
Other exercises in this chapter
Problem 31
Write an equation of an ellipse for the given foci and co-vertices. foci \(( \pm 14,0),\) co-vertices \((0, \pm 7)\)
View solution Problem 31
Write an equation for each conic section. Then sketch the graph. parabola with vertex \((2,-3)\) and focus \((2,5)\)
View solution Problem 31
Graph each equation. Describe the graph and its lines of symmetry. Then find the domain and range. $$ -8 x^{2}+32 y^{2}-128=0 $$
View solution Problem 31
Use the center and the radius to graph each circle. $$ x^{2}+y^{2}=9 $$
View solution