Problem 31
Question
The proposition \(\sim(p \vee-q) \vee \sim(p \vee q)\) is logically equivalent to: (a) \(p\) (b) \(q\) (c) \(\sim p\) (d) \(\sim q\)
Step-by-Step Solution
Verified Answer
The given proposition is logically equivalent to (c) \(\sim p\).
1Step 1: Apply De Morgan's Law
Recall De Morgan's Law: \[ \sim(p \vee q) \equiv \sim p \wedge \sim q \]\ Use De Morgan's Law to transform the first negation: \[ \sim(p \vee -q) \] becomes \[ \sim p \wedge \sim(-q) \] which simplifies to \[ \sim p \wedge q \] by noting that \(\sim(-q)\) is \(q\).
2Step 2: Use De Morgan's Law Again
Apply De Morgan's Law to the second part: \[ \sim(p \vee q) \] becomes \[ \sim p \wedge \sim q \].
3Step 3: Apply Distributive Law
Now consider the expression with negations applied: \[ (\sim p \wedge q) \vee (\sim p \wedge \sim q) \]Use distribution over \( \vee \):Factor out \(\sim p\): \[ \sim p \wedge (q \vee \sim q) \]
4Step 4: Simplify Using Tautology
Recognize that the expression \(q \vee \sim q\) is a tautology, meaning it is always true. Therefore:\[ \sim p \wedge (q \vee \sim q) \] simplifies to \(\sim p\).
5Step 5: Conclusion
Thus, the original proposition \(\sim(p \vee -q) \vee \sim(p \vee q)\) is logically equivalent to \(\sim p\).
Key Concepts
Propositional LogicDe Morgan's LawsTautologyDistributive Law
Propositional Logic
Propositional logic is a branch of logic that deals with propositions, which are statements that can either be true or false. In propositional logic, we utilize variables such as \( p \) and \( q \) to represent different propositions. Logical operations such as AND (\( \wedge \)), OR (\( \vee \)), and NOT (\( \sim \)) are used to form more complex expressions from these propositions.
For example, \( \sim p \) signifies "not \( p \)", indicating that if \( p \) is true, then \( \sim p \) is false, and vice versa. Through the combination of these operations, propositional logic allows us to evaluate the truth values of compound statements.
For example, \( \sim p \) signifies "not \( p \)", indicating that if \( p \) is true, then \( \sim p \) is false, and vice versa. Through the combination of these operations, propositional logic allows us to evaluate the truth values of compound statements.
De Morgan's Laws
De Morgan's Laws are crucial rules in propositional logic that facilitate the process of transforming logical expressions. These laws help simplify complicated propositions, making the logic easier to manage. They state the following:
This is a fundamental technique enabling us to manipulate and find logical equivalences.
- \( \sim (p \vee q) \equiv (\sim p \wedge \sim q) \)
- \( \sim (p \wedge q) \equiv (\sim p \vee \sim q) \)
This is a fundamental technique enabling us to manipulate and find logical equivalences.
Tautology
In logical terms, a tautology is a statement that holds true under every possible interpretation. No matter how the individual propositions are evaluated, a tautology remains true. A common example of a tautology is the expression \( q \vee \sim q \). This expression will always evaluate to true since at least one of \( q \) or \( \sim q \) must be true at any given time.
In the context of the solution, recognizing \( q \vee \sim q \) as a tautology allowed us to greatly simplify our expression to just \( \sim p \). Understanding tautologies is key in simplifying logical expressions, as they reveal parts of a logic statement that don't influence the overall truth value.
In the context of the solution, recognizing \( q \vee \sim q \) as a tautology allowed us to greatly simplify our expression to just \( \sim p \). Understanding tautologies is key in simplifying logical expressions, as they reveal parts of a logic statement that don't influence the overall truth value.
Distributive Law
The distributive law is one of the rules of propositional logic that involves distributing a logical operator across another operation. It's similar to the distributive property in arithmetic, where \( a(b + c) = ab + ac \). In logic, the distributive law can be expressed with AND and OR operations:
- \( p \wedge (q \vee r) \equiv (p \wedge q) \vee (p \wedge r) \)
- \( p \vee (q \wedge r) \equiv (p \vee q) \wedge (p \vee r) \)
Other exercises in this chapter
Problem 29
The statement \(-(p \leftrightarrow-q)\) is: (a) a tautology (b) a fallacy (c) eqivalent to \(p \leftrightarrow q\) (d) equivalent to \(\sim p \leftrightarrow q
View solution Problem 30
Let \(p, q, r\) denote arbitrary statements. Then the logically equivalent of the statement \(p \Rightarrow(q \vee r)\) is: (a) \((p \vee q) \Rightarrow \mathrm
View solution Problem 32
Consider Statement-1: \((p \wedge \sim q) \wedge(\sim p \wedge q)\) is a fallacy. Statement- \(2:(p \rightarrow q) \leftrightarrow(\sim q \rightarrow \sim p)\)
View solution Problem 33
Let \(p\) and \(q\) be any two logical statements and \(\mathrm{r}: \mathrm{p} \rightarrow(-p \vee q) .\) If \(r\) has a truth value \(F\), then the truth value
View solution