Problem 30
Question
Let \(p, q, r\) denote arbitrary statements. Then the logically equivalent of the statement \(p \Rightarrow(q \vee r)\) is: (a) \((p \vee q) \Rightarrow \mathrm{r}\) (b) \((p \Rightarrow q) \vee(p \Rightarrow r)\) (c) \((p \Rightarrow \sim q) \wedge(p \Rightarrow r)\) (d) \((p \Rightarrow q) \wedge(p \Rightarrow \sim r)\)
Step-by-Step Solution
Verified Answer
The logically equivalent statement is (b): \((p \Rightarrow q) \vee(p \Rightarrow r)\).
1Step 1: Understand the Implication
The given statement is an implication: \( p \Rightarrow (q \vee r) \). This means if \( p \) is true, then \( q \vee r \) must also be true.
2Step 2: Apply Logical Equivalence of Implication
Recall that the statement \( A \Rightarrow B \) is logically equivalent to \( \sim A \vee B \). Thus, \( p \Rightarrow (q \vee r) \) can be rewritten as \( \sim p \vee (q \vee r) \).
3Step 3: Simplify Using Distributive Law
Use the associative and distributive laws to simplify: \( \sim p \vee (q \vee r) \equiv (\sim p \vee q \vee r) \).
4Step 4: Identify Equivalent Statement
From the rewritten form \( \sim p \vee q \vee r \), look for an answer choice that matches. The logical equivalence of distributive and De Morgan's laws suggests that this is equivalent to statement (b): \((p \Rightarrow q) \vee(p \Rightarrow r)\).
5Step 5: Verify with Truth Table
For full verification, you could construct a truth table for both \( p \Rightarrow (q \vee r) \) and \((p \Rightarrow q) \vee(p \Rightarrow r)\), finding that they're always the same under all combinations of truth values for \( p, q, \) and \( r \).
Key Concepts
Logical ImplicationTruth TableDe Morgan's LawsDistributive Law
Logical Implication
In logic, an implication, like the statement \( p \Rightarrow (q \vee r) \), is a fundamental construct that needs clear understanding. An implication is a type of conditional statement. It can be interpreted as "if \( p \) is true, then \( q \vee r \) must also be true." This means that whenever \( p \) happens, at least one of \( q \) or \( r \) should occur, or both.
Logically, an implication \( A \Rightarrow B \) can be rewritten using logical equivalence to \( \sim A \vee B \). Here, \( \sim A \) indicates "not A," making the implication equivalent to saying "either A is false, or B is true." This transformation allows us to visualize implications in terms of logical OR operations, facilitating easiness in manipulations and simplifications of logical expressions.
Logically, an implication \( A \Rightarrow B \) can be rewritten using logical equivalence to \( \sim A \vee B \). Here, \( \sim A \) indicates "not A," making the implication equivalent to saying "either A is false, or B is true." This transformation allows us to visualize implications in terms of logical OR operations, facilitating easiness in manipulations and simplifications of logical expressions.
Truth Table
A truth table is a helpful tool in logic to evaluate the truth values of propositions and their combinations. It systematically lists all possible combinations of truth values for the involved statements and shows what each expression evaluates to under those conditions.
For our implication \( p \Rightarrow (q \vee r) \), a truth table would consider all possible truth values of \( p, q, \) and \( r \). We compare these values to those produced by \((p \Rightarrow q) \vee (p \Rightarrow r)\) to confirm they result in identical outcomes.
Truth tables, though conceptually straightforward, are powerful in verifying logical equivalences, such as determining if two expressions yield the same results across all combinations of input values.
For our implication \( p \Rightarrow (q \vee r) \), a truth table would consider all possible truth values of \( p, q, \) and \( r \). We compare these values to those produced by \((p \Rightarrow q) \vee (p \Rightarrow r)\) to confirm they result in identical outcomes.
Truth tables, though conceptually straightforward, are powerful in verifying logical equivalences, such as determining if two expressions yield the same results across all combinations of input values.
De Morgan's Laws
De Morgan's Laws are crucial in understanding how to distribute negations over logical operators. These laws provide a way to transform complex logical statements into simpler equivalent forms. They are stated as:
Often, they serve in simplifying negations by transforming conjunctions and disjunctions, offering clearer insight into the logical structure of complex expressions.
- \( \sim (A \wedge B) \equiv (\sim A \vee \sim B) \)
- \( \sim (A \vee B) \equiv (\sim A \wedge \sim B) \)
Often, they serve in simplifying negations by transforming conjunctions and disjunctions, offering clearer insight into the logical structure of complex expressions.
Distributive Law
The distributive law in logic allows us to distribute one operator over another, often simplifying complex logical expressions. This law is similar to the algebraic distributive property, but it applies to logical operators. Specifically, it tells us:
- \( A \wedge (B \vee C) \equiv (A \wedge B) \vee (A \wedge C) \)
- \( A \vee (B \wedge C) \equiv (A \vee B) \wedge (A \vee C) \)
Other exercises in this chapter
Problem 28
The negation of \(\sim \mathrm{s} \vee(\sim \mathrm{r} \wedge \mathrm{s})\) is equivalent to: (a) \(s \vee(r \vee \sim s)\) (b) s\wedger (c) \(\mathrm{s} \wedge
View solution Problem 29
The statement \(-(p \leftrightarrow-q)\) is: (a) a tautology (b) a fallacy (c) eqivalent to \(p \leftrightarrow q\) (d) equivalent to \(\sim p \leftrightarrow q
View solution Problem 31
The proposition \(\sim(p \vee-q) \vee \sim(p \vee q)\) is logically equivalent to: (a) \(p\) (b) \(q\) (c) \(\sim p\) (d) \(\sim q\)
View solution Problem 32
Consider Statement-1: \((p \wedge \sim q) \wedge(\sim p \wedge q)\) is a fallacy. Statement- \(2:(p \rightarrow q) \leftrightarrow(\sim q \rightarrow \sim p)\)
View solution