Problem 31
Question
For each plane curve, find a rectangular equation. State the appropriate interval for \(x\) or \(y .\) $$x=t+2, y=\frac{1}{t+2}, \text { for } t \neq-2$$
Step-by-Step Solution
Verified Answer
The rectangular equation is \( y = \frac{1}{x} \) with \( x \neq 0 \).
1Step 1: Understand the Parametric Equations
We start with the given parametric equations: \( x = t + 2 \) and \( y = \frac{1}{t+2} \). Our goal is to express \( y \) as a function of \( x \), or vice versa.
2Step 2: Solve for \( t \) in Terms of \( x \)
From the equation \( x = t + 2 \), solve for \( t \) by subtracting 2 from both sides: \( t = x - 2 \).
3Step 3: Substitute \( t \) in the Equation for \( y \)
Take the expression for \( t \) that we found, \( t = x - 2 \), and substitute it into the equation for \( y \): \( y = \frac{1}{t+2} = \frac{1}{(x-2)+2} = \frac{1}{x} \).
4Step 4: Define the Domain for \( x \)
Since \( t eq -2 \), the substitution \( t = x - 2 \) implies \( x - 2 eq -2 \). This simplifies to \( x eq 0 \). Therefore, the domain for \( x \) is all real numbers except 0.
Key Concepts
Rectangular EquationDomain of a FunctionParametric to Rectangular Conversion
Rectangular Equation
In the world of mathematics, a **rectangular equation** is an expression that relates two variables, typically labeled as \( x \) and \( y \), on a Cartesian coordinate plane. This form is usually the result of combining parametric equations, which separately define each variable in terms of a third parameter, often \( t \). The goal of this combination is to produce a single equation that shows the relationship between \( x \) and \( y \) without involving the parameter.In the given example, we start with the parametric equations \( x = t + 2 \) and \( y = \frac{1}{t+2} \). Our task is to eliminate the parameter \( t \) to find a relationship solely between \( x \) and \( y \). By solving the equation for \( t \) in terms of \( x \), \( t = x - 2 \), and substituting this back into the expression for \( y \), we find that the rectangular equation is \( y = \frac{1}{x} \). This shows how the parametric form can be transformed into a simple relationship between the variables.
Domain of a Function
The **domain of a function** is the complete set of all possible input values (usually \( x \)) which allow the function to work without any mathematical inconsistencies, such as division by zero or taking the square root of a negative number. Determining the domain ensures that the output or dependent variable \( y \) will have valid values.For the rectangular equation \( y = \frac{1}{x} \) derived in this exercise, the function's domain is influenced by the parametric restriction \( t eq -2 \). When converting to \( x \), this restriction morphs into \( x eq 0 \), because substituting back, \( t = x - 2 \), implies \( 0 = x \), leading to undefined division. Therefore, the domain of \( y = \frac{1}{x} \) consists of all real numbers except for zero, avoiding undefined expressions.
Parametric to Rectangular Conversion
**Conversion from parametric to rectangular equations** involves eliminating the parameter and expressing the variables \( x \) and \( y \) directly. This conversion is useful for simplifying complex curves into more standard formats that are easier to graph or analyze.In the example provided, we start with two parametric equations: \( x = t + 2 \) and \( y = \frac{1}{t+2} \). Our aim is to combine these into one. By isolating \( t \) from \( x = t + 2 \), we get \( t = x - 2 \). Substituting this value into \( y \)'s equation, we find \( y = \frac{1}{x} \). This process of substitution effectively removes the parameter and reveals how \( x \) and \( y \) interact directly.Through conversion, insights about the curve’s properties—like its domain, slope, or intercepted points—become more readily apparent. Understanding the conversion process enhances our ability to interpret and utilize mathematical models.
Other exercises in this chapter
Problem 30
Graph each circle by hand if possible. Give the domain and range. $$x^{2}+y^{2}=36$$
View solution Problem 31
Find an equation for each ellipse. Center \((3,-2) ; a=5 ; c=3 ;\) major axis vertical
View solution Problem 31
Determine the type of conic section represented by each equation, and graph it, provided a graph exists. $$y^{2}-4 y=x+4$$
View solution Problem 31
Graph each circle by hand if possible. Give the domain and range. $$x^{2}+y^{2}=0$$
View solution