Problem 31
Question
Find an equation for each ellipse. Center \((3,-2) ; a=5 ; c=3 ;\) major axis vertical
Step-by-Step Solution
Verified Answer
The equation of the ellipse is \( \frac{(x-3)^2}{16} + \frac{(y+2)^2}{25} = 1 \).
1Step 1: Understand the Problem
We're given an ellipse with a specific center (\((3, -2)\)), a given semi-major axis length (\(a=5\)), and a given distance from the center to the focus (\(c=3\)). Our task is to find the equation of this ellipse, knowing that the major axis is vertical.
2Step 2: Determine the Form of the Equation
Since the major axis is vertical, the general form of the ellipse's equation will be: \[ \frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2} = 1 \]where \((h, k)\) is the center of the ellipse, \(a\) is the semi-major axis, and \(b\) is the semi-minor axis.
3Step 3: Calculate \(b\) Using the Relationship
The relationship between \(a\), \(b\), and \(c\) in ellipses is given by the equation \(c^2 = a^2 - b^2\).Plugging in the values:\[c = 3, \quad a = 5 \]\[3^2 = 5^2 - b^2\]\[9 = 25 - b^2\]\[b^2 = 16\]\[b = 4\]
4Step 4: Substitute Values into the Ellipse Equation
Now that we have \(b = 4\), and we know the center \((h, k) = (3, -2)\), we substitute these values back into the general equation:\[ \frac{(x-3)^2}{16} + \frac{(y+2)^2}{25} = 1 \]This is the equation of the ellipse with the given parameters.
Key Concepts
Equation of an EllipseMajor and Minor AxesCenter of EllipseFocus of Ellipse
Equation of an Ellipse
The equation of an ellipse is a mathematical expression that defines the set of all points satisfying particular conditions related to distances. An ellipse has two standard forms, depending on the orientation of its major axis, either horizontal or vertical. If the major axis is vertical, as in the problem's example, the equation is:
\[ \frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2} = 1 \]
\[ \frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2} = 1 \]
- \((h, k)\) represents the center of the ellipse.
- \(a\) is the length of the semi-major axis.
- \(b\) is the length of the semi-minor axis.
Major and Minor Axes
In an ellipse, the major and minor axes refer to the longest and shortest diameters, respectively. Here's how they are defined:
- **Major Axis**: The longest line that runs through the center of the ellipse and its foci. In the given problem, since the major axis is vertical, it stretches vertically from one end of the ellipse to the other, crossing through both foci and the center.
- **Minor Axis**: The shortest line through the center that is perpendicular to the major axis. It's also symmetric about the center.
Center of Ellipse
The center of an ellipse is a pivotal point in its geometry. It is the midpoint of both axes:
- It acts as a symmetry point, meaning each half of the ellipse is a mirror image of the other half.
- In the equation of the ellipse \((h, k)\), \(h\) and \(k\) denote the \(x\) and \(y\) coordinates of the center, respectively.
Focus of Ellipse
The focus (plural: foci) of an ellipse is a unique aspect of its structure. These are two points located along the major axis, equidistant from the center. The foci serve as a "gravity center", where the sum of the distances from any point on the ellipse to the foci is constant. Here's more about them:
- The distance from the center to each focus is noted as \(c\).
- In any ellipse, the relationship between \(a\), \(b\), and \(c\) is given by \(c^2 = a^2 - b^2\).
Other exercises in this chapter
Problem 30
Determine the type of conic section represented by each equation, and graph it, provided a graph exists. $$\frac{(x-4)^{2}}{8}+\frac{(y+1)^{2}}{2}=0$$
View solution Problem 30
Graph each circle by hand if possible. Give the domain and range. $$x^{2}+y^{2}=36$$
View solution Problem 31
For each plane curve, find a rectangular equation. State the appropriate interval for \(x\) or \(y .\) $$x=t+2, y=\frac{1}{t+2}, \text { for } t \neq-2$$
View solution Problem 31
Determine the type of conic section represented by each equation, and graph it, provided a graph exists. $$y^{2}-4 y=x+4$$
View solution